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12345 [234]
3 years ago
13

Evaluate 5 + 6 · 2 – 8 ÷ 4 + 7 using the correct order of operations

Mathematics
2 answers:
Natali5045456 [20]3 years ago
8 0
Do solve this you use PEMDAS. This stands for:
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Because there are no parentheses or exponents in this equation, we go straight to the division.

1) 8 divided by 4 equals two so we rewrite the equation. 5+6 x 2 - 2 + 7.

2) Next in order of pemdas is multiplication. Yes I know that in pemdas multiplication does come before division but it doesn’t matter in this problem which you do first. So now we do 6 x2 =12. We then rewrite the equation 5+12-2+7.

3) lastly, addition and subtraction are grouped together and you can just do it in order of the problem. So we do 5+12=17. 17-2=15. And 15+7=22.

So the final answer is: 22
Musya8 [376]3 years ago
3 0

Answer:

(A) 22

Step-by-step explanation:

In solving mathematics using order of operations, BODMAS is a sure compass.

I'll like to work with the decimal point there to mean Multiplication.

Let's fire on!

5 + 6 · 2 – 8 ÷ 4 + 7

I'll like to follow this order:

BRACKET

OF

DIVISION

MULTIPLICATION

ADDITION

SUBTRACTION

The process becomes:

5 + 6 · 2 – 8 ÷ 4 + 7

= 5 + 6 . 2 - 2 + 7

= 5 + 12 - 2 + 7

= 24 - 2

= 22

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Jasper wants to buy a video game that costs $35. He has $10.50, and his weekly allowance is $5. If w represents the number of we
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Determine if the functions are even, odd or neither. f(x) = -5x4 - 2 and g(x) = x3 + 2x
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Try this option:
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2. f(x)=x³+2x.
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5 0
3 years ago
Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a
spin [16.1K]

Answer:

Mean = 68.9

s^2 =18.1 --- Variance

Step-by-step explanation:

Given

\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5

For 59 - 66

x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5

For 67 - 74

x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5

For 75 - 82

x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5

For 83 - 90

x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5

So, the table becomes:

\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}

The mean is then calculated as:

Mean = \frac{\sum fx}{\sum f}

Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}

Mean = \frac{2547.5}{37}

Mean = 68.9 -- approximated

Solving (b): The sample variance:

This is calculated as:

s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}

So, we have:

s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}

s^2 =\frac{652.8}{36}

s^2 =18.1 -- approximated

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