Y=-1/2
Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.<span><span>(y)</span>⋅<span>(6)</span>=<span>(−3)</span>⋅<span>(1<span>)
</span></span></span>Simplify the left side.<span><span>6y=<span>(−3)</span>⋅<span>(1)</span></span><span>6y=<span>(-3)</span>⋅<span>(1)</span></span></span>
Simplify the right side.<span><span>6y=−3</span><span>6y=-3</span></span>
Divide each term by <span>66</span> and simplify.y=-1/2
<u>Answer</u>-
<em>The total capacitive reactance of the circuit is </em><em>7.96 Ω.</em>
<u>Solution-</u>
Two capacitors, a 20 mF and a 30 mF, are connected in parallel to a 400 Hz source.
The effective/equivalent capacitance of the circuit is,
As, when capacitors are connected together in parallel, the equivalent capacitance in the circuit is equal to the sum of capacitance of all the individual capacitor.
We know that,
Where,
= Capacitive Reactance (in Ω)
f = frequency (in Hz)
C = Capacitance (in F)
Here given,
= ??
f = 400 Hz
C = 50 mF = 
F
Putting the values in the formula,
Therefore, the total capacitive reactance of the circuit is 7.96 Ω.
Answer:
it would be 53
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
13/52*13/52*13/521=2197/140608 (1/64)
A, he had just eaten
B, he was shot in the back
E, the arrow went under his left armpit
This all is correct considering the paragraph i just read!
I wish you luck on the rest of your assessment!
mark this as brainliest if i helped at all!! :)
