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andrew11 [14]
3 years ago
8

A color printer prints 34 pages in 11 minutes. How many minutes does it take per page ?

Mathematics
2 answers:
Anna35 [415]3 years ago
5 0

Answer:

3.0909090909 repeating

=3.09

Step-by-step explanation:

please mark me brainliest if this is right :)

Ilya [14]3 years ago
4 0

Answer:

34 divided by 11 is 3.09

Step-by-step explanation:

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PLEASE HELP ILL DO ANYTHING PLEASE. ill give brainliest
Amanda [17]

Answer:

If the ball cost 10 cents and the bat costs $1.00 more than the ball, then the bat would cost $1.10 for a grand total of $1.20. The correct answer to this problem is that the ball costs 5 cents and the bat costs — at a dollar more — $1.05 for a grand total of $1.10.

'Now give me brainiest

8 0
3 years ago
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3x+y=7<br> 6x+4y=22<br> can somebody help me solve this problem?
swat32
Hey there!

\boxed{x=1;y=4}

3x + y = 7 \\ \\ &#10;    6x + 4y = 22

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5 0
3 years ago
Evaluate -8w + 3z when w = 2.2 and z = -9.1.
atroni [7]
-8w+3z
w=2.2
z=-9.1

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8 0
3 years ago
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Factor the following polynomial 9x2 + 21x – 18
solong [7]

Answer:

factors are

21 and x

Step-by-step explanation:

equation 9 × 2 + 21x - 18

terms 9 , 2, 21x, -18

factors 21x = 21 and x

4 0
3 years ago
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A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

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2 years ago
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