Answer:
$2000
Step-by-step explanation:
6,000 dollars is invested in two different accounts earning 3% and 5% interest.
Let x be the amount invested in account earning 3% interest
So, 6000-x is the amount invested in account earning 5% interest

So, Simple interest for account earning 3% interest


Simple interest for account earning 5% interest



Since we are given that the two accounts earned $220 in interest
So, 




So, 4000 was invested at 3%
(6000-x)=6000-4000=2000 was invested at 5%
Hence 2000 was invested at 5%
Answer:
Step-by-step explanation:
They are both C3H8
There are
3 carbons
8 hydrogens
Or put in the form that the table is written
Element # of atoms
Hydrogen 8
Carbon 3
Answer:
yeah sure
Step-by-step explanation:
D because there’s a pattern. Pattern for x is that it’s adding by one. Pattern for y is that it’s adding by 15
Answer:
I'm going to paint you a picture in words of what this looks like on paper. We have a train leaving from a point on your paper heading straight west. We have another train leaving from the same point on your paper heading straight east. This is the "opposite directions" that your problem gives you.
Now let's make a table:
distance = rate * time
Train 1
Train 2
We will fill in this table from the info in the problem then refer back to our drawing. It says that one train is traveling 12 mph faster than the other train. We don't know how fast "the other train" is going, so let's call that rate r. If the first train is travelin 12 mph faster, that rate is r + 12. Let's put that into the table
distance = rate * time
Train 1 r
Train 2 (r + 12)
Then it says "after 2 hours", so the time for both trains is 2 hours:
distance = rate * time
Train 1 r * 2
Train 2 (r + 12) * 2
Since distance = rate * time, the distance (or length of the arrow pointing straight west) for Train 1 is 2r. The distance (or length of the arrow pointing straight east) for Train 2 is 2(r + 12) which is 2r + 24. The distance between them (which is also the length of the whole entire arrow) is 232. Thus:
2r + 2r + 24 = 232 and
4r = 208 so
r = 52
This means that Train 1 is traveling 52 mph and Train 2 is traveling 12 miles per hour faster than that at 64 mph
Step-by-step explanation: