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First off, consecutive integer and can be written as n, n+1 and n+2
(try putting a number in for n if it does not make sense yet)
The sum of the first and twice the second would be n+2(n+1)
So, our equation becomes
n+2(n+1)=110-3(n+2)
n+2n+2=110-3n-6
3n+2=104
6n=102
n=17
so, our three term are 17,18 and 19
Step-by-step explanation:
x² - 14x - 51 = 0
(x² - 17x) + (3x - 51) = 0
x(x - 17) + 3(x - 17) = 0
(x + 3) (x - 17) = 0
x + 3 = 0 eq1
x = 0 - 3
x = -3
x - 17 = 0 eq1
x = 0 + 17
x = 17