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3 years ago

Another easy one

1 answer:

4 0

The limit is equivalent to the value of the derivative of $\cos x$ at $x=\dfrac\pi2$ . (See definition of derivative)

$(\cos x)'=-\sin x\implies (\cos x)'\bigg|_{x=\pi/2}=-\sin\dfrac\pi2=-1$

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△JKL∼△STU Which statements are true? more than one are right (ps the line means similar to)

drek231 [11]

The correct answers are

m<J = m<S
<K = <T
KL/TC = JK/ST

7 0

3 years ago

Read 2 more answers

What is 144÷8 in distributive property

aivan3 [116]

18 it is this please look144÷8=18

6 0

3 years ago

Help me out please?<br>chapter : exponents and powers

belka [17]

Answer:

$\frac{125}{27}$

Step-by-step explanation:

$\frac{2^{-4} \times 15^{-3} \times 625}{5^2 \times 10^{-4}}$

Lets expand all the composite numbers into prime numbers.

$=> \frac{2^{-4} \times (3^{-3} \times 5^{-3}) \times 5^4}{5^2 \times (2^{-4} \times 5^{-4})}$

Lets cancel $2^{-4}$ from numerator and denominator.

$=> \frac{3^{-3} \times 5^{-3} \times 5^4}{5^2 \times 5^{-4}}$

Using laws of exponents , lets solve this.

$=> \frac{3^{-3} \times 5^{(-3 + 4)}}{5^{( 2 - 4)}}$

$=> \frac{3^{-3} \times 5^{1}}{5^{-2}}$

$=> 3^{-3} \times 5^{[1 - (-2)]}$

$=> 3^{-3} \times 5^{3}$

$=> \frac{5^3}{3^3} = \frac{125}{27}$

4 0

3 years ago

Read 2 more answers

An arhitect wants to draw a rectangle with a diagonal of 20 inches. The length of the rectangle is to be 8 inches more than twic

kiruha [24]

The diagonal of a rectangle = sqrt(w^2 + l^2)

w = width

l = length

In this problem,

The diagonal = 20 in

w = x

l = 2x + 8

Let's plug our numbers into the formula above.

20in = sqrt((x)^2 + (2x + 8)^2)

Let's simplify the inside of the sqrt

20 in = sqrt(5x^2 + 32x + 64)

Now, let's square both sides.

400 = 5x^2 + 32x + 64

Subtract 400 from both sides.

0 = 5x^2 + 32x - 336

Factor

0 = (5x - 28)(x + 12)

Set both terms equal to zero and solve.

x + 12 = 0

Subtract 12 from both sides.

x = -12

5x - 28 = 0

Add 28 to both sides.

5x = 28

Divide both sides by 5

x = 28/5

The width cant be a negative number so now we know that the only real solution is 28/5

Let's plug 28/5 into our length equation.

Length = 2(28/5) + 8 = 56/5 + 8 = 96/5

In conclusion,

Length = 96/5 inches

Width = 28/5

4 0

3 years ago

On number 19 this needs to be shown full work I don’t know where to start can someone help me now ASAP!!!

DENIUS [597]

Answer:

sorry if I'm wrong, I'm in the 7th grade lol, did my best :) hope I sortof helped

Step-by-step explanation:

5-2=3

square root of 3 with 3 is 1

$5 - 2 = 1 \\ 3 \sqrt{3 = 1}$

7 0

3 years ago