The width of the path is 4 meters.
<h3>How to find the width of the path?</h3>
The pool is measuring 8 meters by 26 meters is surrounded by a path of uniform width.
The area of the pool and the path combined is 544 square meters.
Therefore, The dimensions of pool are 8 meters and 26 meters as it is surrounded by a path of uniform width, let the width be x meters and
the dimensions of the pool and the path combined will be
8 + 2x and 26 + 2x and as area is 544 m²
, the equation is
(8 + 2x)(26 + 2x) = 544
208 + 16x + 52x + 4x² = 544
4x² + 68x - 544 + 208 = 0
4x² + 68x - 336 = 0
4(x² + 17x - 84) = 0
x² + 17x - 84 = 0
Hence,
(x - 4)(x + 21)
Therefore,
x = 4 and x = -21
As width of path cannot be negative, it is 4 meters.
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Answer:
104.7 in^3
Step-by-step explanation:
Step one:
given data
The ball has a radius of 5 inches and
the cylinder has a height of 8 inches
Step two:
The volume of the cylinder
substitute our data
The volume of the ball
substitute our data
The space will have a volume of
=628.4-523.7
=104.7 in^3
Answer:
170
Step-by-step explanation:
First, find the area of the rectangles. It's length is 10, and the width is 5. Multiply them to get an area of 50. Since there are 3 congruent rectangles, multiply that by 3. Then find the area of the triangle. It's height is 4, and the base is 5. Multiply and divide by 2, giving you 10. Since there is a congruent triangle add 10 again, as well as the area of the 3 rectangles.
50+50+50+10+10 = 170