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2 years ago

If 1503 kg of rice was packed in sacks weighing 3 kg each, how many sacks were packed

Mathematics

1 answer:

AURORKA [14]2 years ago

6 0

Answer:

501 sacks

Step-by-step explanation:

please mark me as brainlest

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Which polynomial is written in ascending order?

Molodets [167]

What are the options for this question?

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3 years ago

Find 10 partial sums of the series. (round your answers to five decimal places.) ∞ 15 (−4)n n = 1

nikklg [1K]

Given

$\Sigma_{n=1}^\infty15(-4)^n$

The first 10 partial sums are as follows:

$S_1=\Sigma_{n=1}^{1}15(-4)^n=15(-4)=\bold{-60} \\ \\ S_2=\Sigma_{n=1}^{2}15(-4)^n=\Sigma_{n=1}^{1}15(-4)^n+15(-4)^2 \\ =-60+15(16)=-60+240=\bold{180} \\ \\ S_3=\Sigma_{n=1}^{3}15(-4)^n=\Sigma_{n=1}^{2}15(-4)^n+15(-4)^3 \\ =180+15(-64)=180-960=\bold{-780} \\ \\ S_4=\Sigma_{n=1}^{4}15(-4)^n=\Sigma_{n=1}^{3}15(-4)^n+15(-4)^4 \\ =-780+15(256)=-780+3,840=\bold{3,060} \\ \\ S_5=\Sigma_{n=1}^{5}15(-4)^n=\Sigma_{n=1}^{4}15(-4)^n+15(-4)^5 \\ =3,060+15(-1,024)=3,060-15,360=\bold{-12,300}$

$S_6=\Sigma_{n=1}^{6}15(-4)^n=\Sigma_{n=1}^{5}15(-4)^n+15(-4)^6 \\ =-12,300+15(4,096)=-12,300+61,440=\bold{49,140}$

The rest of the partial sums can be obtained in similar way.

7 0

3 years ago

Aahil, James and merav share £90 in the ratio 1:3:5 how much does merav get

Dafna1 [17]

Given: £90 is divided among Aahil, James and Merav in the ratio 1:3:5.

To find: How much Merav gets.

Answer:

Let's assume the shares of each to be 'x'.

This implies that 1x + 3x + 5x = 90.

9x = 90

x = 90/9

x = 10

Substituting this value of x in the ratio,

1 × 10 = 10 [Aahil's share]
3 × 10 = 30 [James' share]
5 × 10 = 50 [Merav's share]

Therefore, Merav gets £50.

Hope it helps. :)

8 0

2 years ago

What's the explicit rule for the sequence 3, -6, 12, -24, 48, ...?

777dan777 [17]

Answer:

$\sf \dfrac{-3}{2}(-2)^n$

Step-by-step explanation:

Explicit formulas are used to represent all the terms of the geometric sequence with a single formula.

$\sf \boxed{\bf t_n = ar^{n-1}}$

a is the first term.

r is the common ratio.

r = second term ÷ first term.

3 , - 6 , 12, - 24, 48 ,........

a = 3

r = -6 ÷ 3 = -2

$\sf t_n = 3*(-2)^{(n-1)}\\\\$

$\sf = 3*(-2)^{n}*(-2)^{-1}\\\\ =3*(-2)^n*\dfrac{-1}{2}\\\\= \dfrac{-3}{2}(-2)^n$

Check:

$\sf t_1 =\dfrac{-3}{2}*(-2)^1=\dfrac{-3}{2}*(-2) = 3\\\\\\t-2 = \dfrac{-3}{2}*(-2)^2 = \dfrac{-3}{2}*4=-6\\\\\\t_3=\dfrac{-3}{2}*(-2)^3=\dfrac{-3}{2}*(-8)=12$

4 0

1 year ago

Read 2 more answers

What is the equation of the line? Identify the values of A, B, and C in the

notsponge [240]

Answer:

-1

Step-by-step explanation:

6 0

3 years ago

If 1503 kg of rice was packed in sacks weighing 3 kg each, how many sacks were packed￼￼￼￼

If 1503 kg of rice was packed in sacks weighing 3 kg each, how many sacks were packed