If 1503 kg of rice was packed in sacks weighing 3 kg each, how many sacks were packed

Paul owns a mobile wood-fired pizza oven operation. A couple of his clients complained about his dough at a recent catering, so

Makovka662 [10]

Answer: B. Do not reject H0, we cannot conclude the proportion of customer complaints is more for the old dough

Step-by-step explanation:

This is a test of 2 population proportions. Let 1 and 2 be the subscript for the old and the new dough players. The population proportions of customer complaints with the old and new dough would be p1 and p2

P1 - P2 = difference in the proportion of customer complaints with the old and new dough.

The null hypothesis is

H0 : p1 ≥ p2

pm - pw ≥ 0

The alternative hypothesis is

Ha : p1 < p2

p1 - p2 < 0

it is a left tailed test

Sample proportion = x/n

Where

x represents number of success(number of complaints)

n represents number of samples

For old dough

x1 = 6

n1 = 385

P1 = 6/385 = 0.016

For new dough,

x2 = 16

n2 = 340

P2 = 16/340 = 0.047

The pooled proportion, pc is

pc = (x1 + x2)/(n1 + n2)

pc = (6 + 16)/(385 + 340) = 0.03

1 - pc = 1 - 0.03 = 0.97

z = (Pm - Pw)/√pc(1 - pc)(1/nm + 1/nw)

z = (0.016 - 0.047)/√(0.03)(0.97)(1/385 + 1/340) = - 0.031/√0.00553857907

z = - 0.42

Since it is a left tailed test, we would find the p value for the area to the left of the z score. From the normal distribution table,

p value = 0.337

For a 95% confidence level, the significant level, alpha is

1 - 0.95 = 0.05

Since 0.05 < 0.337, we would accept the null hypothesis

Therefore, Do not reject H0, we cannot conclude the proportion of customer complaints is more for the old dough

7 0

3 years ago

Which of the following points lies on the graph of y = 3x-5

andreyandreev [35.5K]

Answer:

(4,7)

Step-by-step explanation:

I have attached what the graph looks like below.

Looking at it, you will see the point (4,7) lies on the graph.

So the answer is 2)

6 0

2 years ago

A population has a mean of 300 and a standard deviation of 70. Suppose a sample of size 125 is selected and is used to estimate

Mrrafil [7]

Answer:

a: 0.8884

b: 0.9934

Step-by-step explanation:

We have µ = 300 and σ = 70. The sample size, n = 125.

For the sample to be within 8 units of the population mean, we would have sample values of 292 and 308, so we want to find:

P(292 < x < 308).

We need to find the z-scores that correspond to these values using the given data. See attached photo 1 for the calculation of these scores.

We have P(292 < x < 308) = 0.8884

Next we want the probability of the sample mean to be within 17 units of the population mean, so we want the values from 283 to 317. We want to find

P(283 < x < 317)

We need to find the z-scores that correspond to these values. See photo 2 for the calculation of these scores.

We have P(283 < x < 317) = 0.9934

5 0

3 years ago

Three times the quantity five less than x, divided by the product of six and x

Elden [556K]

Answer:

$\frac{3(x-5)}{6x}$

Step-by-step explanation:

we know that

The phrase "Three times the quantity five less than x" means 3 multiplied by the difference of x minus 5

3(x-5)

The phrase "the product of six and x" means the number 6 multiplied by x

6x

therefore

The phrase" Three times the quantity five less than x, divided by the product of six and x" is equal to the quotient of 3(x-5) and 6x

$\frac{3(x-5)}{6x}$

7 0

3 years ago

A cable provider wants to contact customers in a particular telephone exchange to see how satisfied they are with the new digita

dusya [7]

Answer:

a) uniform

b) 1/2

c) 1/1000

Step-by-step explanation:

a) "numbers with equal probability" have a uniform distribution.

__

b) Even numbers make up 1/2 of all numbers.

__

c) There are ten such numbers in the range, so the probability is ...

10/10000 = 1/1000

7 0

3 years ago

If 1503 kg of rice was packed in sacks weighing 3 kg each, how many sacks were packed￼￼￼￼

If 1503 kg of rice was packed in sacks weighing 3 kg each, how many sacks were packed