Match each whole number with a rational, exponential expression.

Mathematics

2 answers:

mixas84 [53]3 years ago

8 0

Answer:

The matches are not given but these can be written in exponent form like below:

1. 256 can be written as $16\times16=16^{2}$

2. 9 = $3\times3=3^{2}$

3. 16 = $4\times4=4^{2}$

4. 25 = $5\times5=5^{2}$

5. 225 = $15\times15=15^{2}$

6. 196 = $14\times14=14^{2}$

Sedbober [7]3 years ago

3 0

1)16^2 or 4^4
2)3^2
3)4^2
4)5^2
5)15^2
6)14^2

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WITCHER [35]

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A 2-column table with 6 rows. The first column is labeled miles driven with entries 27, 65, 83, 109, 142, 175. The second column

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Answer:

1) The linear regression model is y = -0.0348·x + 13.989

2) The correlation coefficient is -0.0725

3) The strength of the model is strong - association

Step-by-step explanation:

X Y XY X²

27 13 351 729

65 12 780 4225

83 11 913 6889

109 10 1090 11881

142 9 1278 20164

175 8 1400 30625

∑ 601 63 5812 74513

From y = ax + b, we have

$a = \frac{n\sum xy - \sum x\sum y }{n\sum x^{2}-\left (\sum x \right )^{2}} = \frac{6 \times 5812 - 601 \times 63}{6 \times 74513-601^{2}} = - 0.0348$

b = 1/n(∑y -a∑x) = 1/6(63 - (0.0348)×601) = 13.989

Therefore, the linear regression model is y = -0.0348·x + 13.989

$r = \frac{n\sum xy - \sum x\sum y }{\sqrt{[n\sum x^{2}-\left (\sum x \right )^{2}] [n\sum y^{2}-\left (\sum y \right )^{2}]}} = \frac{6 \times 5812 - 601 \times 63}{\sqrt{[6 \times 74513-601^{2}] [6 \times 3969 - 63^2]} } = - 0.0725$