3 years ago

How is the product related to the first factor?

Mathematics

1 answer:

NARA [144]3 years ago

5 0

Answer:

5/5 austin

Step-by-step explanation:

You might be interested in

In a right triangle, sin(40 - 2) = cos(32)'. What is the value of x?

o-na [289]

Answer:

x = 25

Step-by-step explanation:

Correct question

In a right triangle Sin (40-x)=cos(3x) what is the value of x

Since Sin theta = Cos(90-theta)

Sin (40-x) = Sin(90-3x)

40 - x = 90 - 3x

-x+3x = 90 - 40

2x = 50

x = 25

Hence the value of x is 25

5 0

3 years ago

Convert the quadratic equation, f (x) = 2(x - 3)2 +1, into standard form.

laiz [17]

Step-by-step explanation:

........4x-y=11........

8 0

3 years ago

Difference of 8 Let's dig into this and find out for sure. First think of two numbers that have a difference of 8. Type the LARG

Serhud [2]

Answer:

16

Step-by-step explanation:

We need to find 2 numbers that have a difference of 8.

Let take's 16 and 8.

As we know :

⇒ 16 - 8

⇒ 8

The larger of these 2 numbers is 16

5 0

2 years ago

Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth

pav-90 [236]

Answer:

$\sqrt{13}$ units

Step-by-step explanation:

The distance formula is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where $d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$ . Let $(x_1,y_1)\rightarrow(5,1)$ and $(x_2,y_2)\rightarrow(3,4)$ , thus:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(3-5)^2+(4-1)^2}\\\\d=\sqrt{(-2)^2+(3)^2}\\\\d=\sqrt{4+9}\\\\d=\sqrt{13}$

Therefore, the distance between points P(5,1) and Q(3,4) is $\sqrt{13}$ units.

8 0

3 years ago

Hi. I need help. This is for homework I would appreciate it if you helped.

Triss [41]

Answer:

Ik this isn't an answer but wanted to say good luck im battling stuff too :(

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers