Answer:
93.75% i hope that helps
Step-by-step explanation:
If their mean is 5, then the numbers add up to 25.
Here are a few sets that do the job:
1, 2, 3, 4, 15
10, 20, 30, 40, -75
+2, -2, +99, -99, 25
1, 5, 5, 5, 9
Answer:
A customer who sends 78 messages per day would be at 99.38th percentile.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Average of 48 texts per day with a standard deviation of 12.
This means that 
a. A customer who sends 78 messages per day would correspond to what percentile?
The percentile is the p-value of Z when X = 78. So



has a p-value of 0.9938.
0.9938*100% = 99.38%.
A customer who sends 78 messages per day would be at 99.38th percentile.
Answer:
y-1=
(x+8)
Step-by-step explanation:
1. y-y1=m(x-x1) (point slope form)
2. y1 is the y of your given point and x1 is the x of your given point
3. m is the slope