Answer:
![\large\boxed{V=75\ in^3}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BV%3D75%5C%20in%5E3%7D)
Step-by-step explanation:
The formula ogf a volume of a pyramid:
![V=\dfrac{1}{3}BH](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B1%7D%7B3%7DBH)
B - area of a base
H - height
We have a base length a = 5 in and a height H = 9 in.
In the base we have a square. The formula of an area of a square is:
![B=a^2](https://tex.z-dn.net/?f=B%3Da%5E2)
Substitute:
![B=5^2=25\ in^2](https://tex.z-dn.net/?f=B%3D5%5E2%3D25%5C%20in%5E2)
Calculate the volume:
![V=\dfrac{1}{3}(25)(9)=(25)(3)=75\ in^3](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B1%7D%7B3%7D%2825%29%289%29%3D%2825%29%283%29%3D75%5C%20in%5E3)
3x - y + z = 5 . . . (1)
x + 3y + 3z = -6 . . . (2)
x + 4y - 2z = 12 . . . (3)
From (2), x = -6 - 3y - 3z . . . (4)
Substituting for x in (1) and (3) gives
3(-6 - 3y - 3z) - y + z = 5 => -18 - 9y - 9z - y + z = 5 => -10y - 8z = 23 . . (5)
-6 - 3y - 3z + 4y - 2z = 12 => y - 5z = 18 . . . (6)
(6) x 10 => 10y - 50z = 180 . . . (7)
(5) + (7) => -58z = 203
z = 203/-58 = -3.5
From (6), y - 5(-3.5) = 18 => y = 18 - 17.5 = 0.5
From (4), x = -6 - 3(0.5) - 3(-3.5) = -6 - 1.5 + 10.5 = 3
x = 3, y = 0.5, z = -3.5
Answer:
(1,-1)
Step-by-step explanation:
-2x-1 = x+2
-3x = 3
x = -1
substitute
y = (-1) + 2
y = 1
point: (1,-1)
Maximum time allowed = 7 deg. / 0.03 deg/s = 233.3 s
Minimum speed = 55 yd * 3 ft/yd / 233.3 s
= 0.707 ft/s