A figure formed by 3 segments connecting 3 non-colinear points
Answer:
y = 1
Step-by-step explanation:
Find the slope of the line passing through the points 
and 
The slope of the line is equal to
then
Angle a corresponds to angle e
Angle b corresponds to angle d
Angle c corresponds to angle c
Side ab corresponds to side cd
Side ac corresponds to side ce
Side bc corresponds to side de
To solve this, you must put the equation in slope-intercept form, which is y=mx+b.
To do this, isolate y.
First, subtract 3x from both sides.
3x + 9y = -9
3x + 9y - 3x = 9y
-9 - 3x = -9 - 3x
9y = -9 - 3x
Now, divide both sides by 9.
9y = -9 - 3x
9y / 9 = y
-9 / 9 = -1
-3x / 9 = -0.33x = -1/3x
y = -1 - 1/3x
In y = mx + b form:
y = -1/3x - 1
In slope intercept form, m is the slope.
In our answer, -1/3 is m, so it is the slope.
So the final answer is that the slope is -1/3.
Hope this helps!
Answer:
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Step-by-step explanation:
