12 + 4r-9= 9x + 7

Find the point(s) of intersection between the quadratic function y = x + 4x + 4 and the linear function y = 2x+4.

Andrews [41]

Answer:

(0, 4)

Step-by-step explanation:

To find the intersection of two lines, we want to find the value when they equal each other. To do this, we want to set the equations equal to each other.

First, let's simplify y = x + 4x + 4 by combining the x's.

y = 5x + 4

Now let's set the equations equal to each other. Since they both equal y, we can set the opposite sides equal to each other.

5x + 4 = 2x + 4

Now you want to combine the terms.

[subtract 4] 5x = 2x

[subtract 2x] 3x = 0

Now you want to isolate the x.

[divide by 3] x = 0

Now we want to find y by plugging x = 0 back into the equations.

y = 5(0) + 4

[multiply] y = 0 + 4

[add] y = 4

Check this with the other equation.

y = 2(0) + 4

[multiply] y = 0 + 4

[add] y = 4

Your answer is correct!

(0, 4)

4 0

2 years ago

What should i type it is the top question tho ok ?

taurus [48]

Answer:

first off whats the value of M? second off when you reflect it just flip along either the x or y axis

Step-by-step explanation:

yeet

3 0

2 years ago

Please help. Subject is Pythagorean theorem

pashok25 [27]

3 because I said so and it is correct

8 0

2 years ago

Use the compound interest formulas A= P (1 + r/n) ^nt and A= Pe ^ rt to solve the problem given. Round to the nearest cent. Find

Dennis_Churaev [7]

Answer:

$\$30,460$
$\$30,497$
$\$30,522$
$\$30,535$

Step-by-step explanation:

We know that,

$A=P\left (1+\dfrac{r}{n}\right )^{n\cdot t}$

where,

A = Amount after time t,

P = Principle amount,

r = Rate of interest,

n = Number of times interest is compounded per year,

t = time period in year.

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded semiannually

Here,

P = $25,000

r = 5% = 0.05

n = 2 (as compounded semiannually)

t = 4 years

Putting the values,

$A=25000\left (1+\dfrac{0.05}{2}\right )^{2\times 4}$

$=25000\left (1+0.025\right )^{8}$

$=25000\left (1.025\right )^{8}$

$=\$30,460$

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded quarterly.

Here,

P = $25,000

r = 5% = 0.05

n = 4 (as compounded quarterly)

t = 4 years

Putting the values,

$A=25000\left (1+\dfrac{0.05}{4}\right )^{4\times 4}$

$=25000\left (1+0.0125\right )^{16}$

$=25000\left (1.0125\right )^{8}$

$=\$30,497$

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded monthly.

Here,

P = $25,000

r = 5% = 0.05

n = 12 (as compounded monthly)

t = 4 years

Putting the values,

$A=25000\left (1+\dfrac{0.05}{12}\right )^{12\times 4}$

$A=25000\left (1+\dfrac{0.05}{12}\right )^{48}$

$=\$30,522$

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded continuously.

$A= Pe^{rt}$

where,

A = Amount after time t,

P = Principle amount,

r = Rate of interest,

t = time period in year.

Putting all the values,

$A= 25000e^{0.05\times 4}=\$30,535$

It can be observed that, the frequent we compound the amount, the more we get.

7 0

2 years ago

Please help and thanks

zhenek [66]

a right angle so 90 degrees

6 0

2 years ago

12 + 4r-9= 9x + 7 - 5x