<u>Answer:
</u>
Required five terms of sequence are 19 , 12 , 5 , -2 and -9 .
<u>
Solution:
</u>
Need to find the five terms of the sequence.
Given recursive rule is f(x) = f(x-1) -7
Substituting x = 2 , f(2) = f(2-1)-7
= f(2) = f(1) – 7 ------(1)
Also given that f(2) = 12.
On substituting the given value of f(2) in eq (1) we get
12 = f(1) – 7
f(1) = 12 + 7 = 19
Using given recursive rule and given value of f(2) calculating f(3)
Substituting x = 3 ,
f(3) = f(3-1) – 7
= f(2) – 7
= 12 – 7
= 5
Using given recursive rule and calculated value of f(3) calculating f(4)
Substituting x = 4,
f(4) = f(4-1) – 7
= f(3) – 7
= 5– 7
= -2
Using given recursive rule and calculated value of f(4) calculating f(5)
Substituting x = 5,
f(5) = f(5-1) – 7
= f(4) – 7
= -2– 7
= -9
Hence required five terms of sequence are 19 , 12 , 5 , -2 and -9 .
Ok the first one.....No solution
The word problem......1.90
and the last one......U=4
I hope this helps!!! :)
(8-3)²-(5-2)²
Follow the PEMDAS
P-Parenthesis
E-Exponents
M/D-Multiplication/Division
A/S-Addition/Subtraction
clear the numerals in the parenthesis:
(5)²-(3)²
Now do the exponents:
=25-9
=16
Its just: (5)²-(3)²
X + y = 40.....multiply by -4
4x + 6y = 180
-------------------
-4x - 4y = -160 (result of multiplying by -4)
4x + 6y = 180
------------------add
2y = 20
y = 20/2
y = 10 <===
x = 30
The vertex is (0,-8)
im not sure about axis of symmetry but i don’t think it has one
