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Nataly_w [17]
2 years ago
11

Help me with this please!

Mathematics
1 answer:
ruslelena [56]2 years ago
6 0
Area of the quarter sector 
Area of the entire circle = pi * r^2
Area of the quarter circle = pi r^2 / 4
r = 9
Area of the quarter circle = pi 9^2 / 4
Area of the quarter circle = pi 81/4 = 20.25 pi

Area of the triangle
Area pf the triangle = 1/2 b*h
b = h = r
r = 9
Area of the triangle = 1/2 9 * 9 
Area of teh triangle = 1/2 81
Area of the triangle = 40.5

Area of the shaded area
The shaded area = Area of the 1/4 circle - area of the triangle
The shaded area = (20.24 pi - 40.5)ft^2

 A <<<<<< Answer.
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3 years ago
I need to turn this in in 2 hours please hurry
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Answer:

  2) 162°, 72°, 108°

  3) 144°, 54°, 126°

Step-by-step explanation:

1) Multiply the equation by 2sin(θ) to get an equation that looks like ...

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(w-2) (w+5) <br> I need help I don't understand ...
Phantasy [73]
<h3>Answer: w^2 + 3w - 10</h3>

===============================================

Work Shown:

Let x = w-2

This will allow us to replace the (w-2) with x to get...

(w-2)(w+5)

x(w+5)

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Now replace x with w-2 and distribute again

w(x) + 5(x)

w(w-2) + 5(w-2)

w*w + w*(-2) + 5*w + 5*(-2)

w^2 - 2w + 5w - 10

w^2 + 3w - 10

6 0
2 years ago
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