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denis23 [38]
3 years ago
9

An $18 item is marked down 30% what is the clearance price

Mathematics
2 answers:
ivanzaharov [21]3 years ago
8 0
18×30%=

18×.30=5.4

5.4 is the amount of clearanceyou get from the item
Know you have to subtract $5.40 from $18.00

18-5.4=12.6

The item is know $12.60
Mandarinka [93]3 years ago
8 0
The clearance price is $12.60.

To find the answer you do $18 × 30/100 which is $5.40 then you subtract $5.40 from $18 ($18 - $5.40) to get $12.60
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What are the zeros of the polynomial function f(x) = x3 − 2x2 − 24x?
Morgarella [4.7K]

Answer:

x = 0, x = -4, and x = 6

Step-by-step explanation:

To find the zeros of this polynomial, we can begin by factoring out a common factor of each term. 'x' is a common factor. We can distribute this variable out, giving us:

f(x) = x(x²- 2x- 24)

Now, factor the polynomial inside of the parenthesis into its simplest form. Factors of -24 that add up to -2 are -4 and 6.

f(x) = x( x + 4) (x - 6)

From this, we can derive the zeros x = 0, x = -4 and x = 6.

4 0
3 years ago
PLEASE HELP ME !!!! WILL GIVE BRAINLIEST TO WHOEVER ANSWERS CORRECTLY
Margarita [4]

Answer:

(8x + 1)° + ( 4x+11)° = 180° (linear pair )

8x +1 + 4x +11 = 180

8x + 4x + 1 + 11 = 180

12x + 12 = 180

12x = 180 - 12

12x = 168

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3 years ago
If X is to 9 as eight is to 12 then x is equal to what'
Tems11 [23]

Answer:

X is 6.

Step-by-step explanation:

What we know:

There's a ratio between 8 and 12, which simplifies to 2/3.

So, to find what x is, just multiply 2/3 times 9, to get 6 as x.

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3 years ago
Two lines and a point are guaranteed to be complainer if
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given : AD is ⊥to AB and DC, BC is ⊥ to AB and DC, angle EDC ≅ angle ECD, AD ≅ BC. prove: triangle ADE ≅ triangle BCE
Kamila [148]

Answer:

Hence proved triangle ADE ≅ triangle BCE by Side Angle Side congruent property.

Step-by-step explanation:

Given:

AD ⊥ AB \& CD

BC ⊥ AB \& CD

AD = BC

∴ ∠ A = ∠ B = ∠ C = ∠ D =90°

∠ EDC = ∠ ECD

Solution

∠ C = ∠ BCE + ∠ ECD⇒ equation 1

∠ D = ∠ ADE + ∠ EDC⇒ equation 2

∠ C = ∠ D (given)

Substituting equation 1 and 2 in above equation we get

∠ BCE + ∠ ECD = ∠ ADE + ∠ EDC

But ∠ EDC = ∠ ECD (given)

∴ ∠ ADE = ∠ BCE

ED = EC (∵ base angles are same triangle is isosceles triangle)

Now, In Δ ADE and Δ BCE

AD =BC

∠ ADE = ∠ BDE

ED = EC

∴ By Side Angle Side congruent property

Δ ADE ≅ Δ BCE

6 0
3 years ago
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