During the evaporation

Mathematics

2 answers:

alisha [4.7K]3 years ago

8 0

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Sample lost is equal to ~

$0.983 \: g \: (sample \: \: 1)$

$0.092 \: g \: (sample \: \: 2)$

$0.979 \: g \: (sample \: \: 3)$

If we arrange it in order from least weight lost to most weight lost, we will get ~

$\fbox{Sample 2 < Sample 1 < Sample 3}$

Leto [7]3 years ago

5 0

Answer:

- 0.092g

- 0.979g

- 0.983g

Explanation: 0.83 > 0.979 > 0.092

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bogdanovich [222]

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3 years ago

Please help me on this it’s due

olya-2409 [2.1K]

<h3>Answer: 5 cakes</h3>

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Explanation:

Let's start off converting the mixed number 12 & 1/4 to an improper fraction.

$a \frac{b}{c} = \frac{a*c+b}{c}\\\\12 \frac{1}{4} = \frac{12*4+1}{4}\\\\12 \frac{1}{4} = \frac{49}{4}\\\\$

Do the same for the other mixed number 2 & 1/3.

$a \frac{b}{c} = \frac{a*c+b}{c}\\\\2 \frac{1}{3} = \frac{2*3+1}{3}\\\\2 \frac{1}{3} = \frac{7}{3}\\\\$

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From here, we divide the two fractions. I converted them to improper fractions to make the division process easier.

$\frac{49}{4} \div \frac{7}{3} = \frac{49}{4} \times \frac{3}{7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{49\times 3}{4\times 7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{7\times 7\times 3}{4\times 7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{7\times 3}{4}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{21}{4}\\\\$