Answer:
0.83,0.50
Step-by-step explanation:
Since there are 2 digits in 83, the very last digit is the "100th" decimal place.
So we can just say that .83 is the same as 83/100.
So your final answer is: .83 can be written as the fraction
First example, are those the only equations given?
Simple....
you have:

So...first you know you're trying to find x..
But, you have a square root on one side...to remove this you'd have to square both sides--->>>

Leaving you with....

Move the terms over and set it equal to
zero.
-->>

Factor out a 3...

What multiplies to -12 and adds to 4?
6*-2=-12
6+-2=4
Leaving you with...

Remember you're solving for 0....
3x-2=0
3x-2=0
+2 +2
3x=2

x=
Then-->>
x+2=0
x+2=0
-2 -2
x=-2
Thus, your answer.
Answer:
10.03% probability of getting a cup weighing more than 8.64oz
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

What is the probability of getting a cup weighing more than 8.64oz
This is the 1 subtracted by the pvalue of Z when X = 8.64. So

has a pvalue of 0.8997
1 - 0.8997 = 0.1003
10.03% probability of getting a cup weighing more than 8.64oz
(6-3)/(3-1) = 3/2
3/2 is the slope