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3 years ago

What is the value of X that makes equation true? -5(2x - 3) + 4x = -3x + 6

Mathematics

1 answer:

Alisiya [41]3 years ago

6 0

Answer:

x=3

Step-by-step explanation:

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The 10th term of an arithmetic sequence is 10 and the sum of the first 10 terms is -35. Find the first term a1, and the common d

lina2011 [118]

The first term is − 17 and the common difference is 3

8 0

3 years ago

Two candidates are randomly selected. a. List all the possible outcomes. b. What is the probability that both are qualified? c.

steposvetlana [31]

Question:

Four candidates are to be interviewed for a job. Two of them, numbered 1 and 2, are qualified, and the other two, numbered 3 and 4, are not.

Answer:

a. S = {12,13,14,23,24,34}

b. 1/6

c. ⅔

Step-by-step explanation:

Let S = Sample Space i.e. total possible outcomes

Given that candidates 1 and 2 are qualified and 3 and 4 are not qualified.

If two candidates are randomly selected. The list of all possible outcomes is as follows

S:{12,13,14,23,24,34}

And the number of outcomes is 6

b. What is the probability that both are qualified?

The event that both are qualified is given as {12} or {21}

From the sample space in (a) above, there's only one occurrence of {12} = 1

So, the probability is calculated as 1/6

c. What is the probability that exactly one is qualified?

The event that one one is qualified is given as {13,14,23,24}

Total = 4

Probability = 4/6

Probability = ⅔

5 0

3 years ago

Two cargo ships are sailing a direct course into harbor. Ship A is 22 miles from harbor. Ship Bis sailing into harbor on a cours

s344n2d4d5 [400]

Answer:

The distance of ship B from the Harbor is 32.26 miles

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.

I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the <u>COSINE operator</u> to solve for the length of the course of ship B.

$cos(x) = \frac{adjacent}{hypotenuse}$

$cos(47) = \frac{22miles}{hypotenuse}$ .... flip both fractions.

$\frac{1}{cos(47)} = \frac{hypotenuse}{22miles}$ .... multiply both sides by 22

$\frac{22mi}{cos(47)} = hypotenuse$

$32.26mi = hypotenuse = B$

So the distance of ship B from the Harbor is 32.26 miles

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

3 0

3 years ago

Suppose you invest $10,400 in equipment to manufacture a new board game. Each game costs $2.65 to manufacture and sells for $20.

tamaranim1 [39]

Answer: 599.42 games
To answer this question, you need to calculate the revenue for every game sold first. The calculation would be:
Revenue= sell cost - manufacture cost= $20-$2.65= $17.35/game.

Break even is the point when the game manufacturing cost(equipment cost included) is covered by the revenue you got. Then the calculation would be:

total game cost= revenue per game * number of game sold
$10400= number of game sold * $17.35
number of game sold= 10400/17.35= 599.42 games

3 0

3 years ago

The length of a rectangle is shown below:

uranmaximum [27]

Sorry if I get this wrong but if your trying to make a rectangle wouldn't it bc (-3,1) and (1,1)?

6 0

3 years ago

What is the value of X that makes equation true? -5(2x - 3) + 4x = -3x + 6￼

What is the value of X that makes equation true? -5(2x - 3) + 4x = -3x + 6