In the equation: (16)^3=2^3/2x how could you solve for x?
1 answer:
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The circumference of the outer edge of the path around the pool is 113.04 ft.
<h3>What is the circumference?</h3>The Circumference (or) perimeter of circle = 2πR. where, R is the radius of the circle.
Given
A circular swimming pool has a radius of 15 ft.
There is a path all the way around that pool that is three feet wide.
A circle has a radius of 15 feet.
A larger circle goes around the smaller circle that is 3 feet wide.
The radius of the outer edge of the path around the pool = Radius of circle + width of outer circle.
The radius of the outer edge of the path around the pool = 15 + 3
The radius of the outer edge of the path around the pool = 18ft
The circumference of the outer edge of the path around the pool is;
Hence, the circumference of the outer edge of the path around the pool is 113.04 ft.
To know more about circumference click the link given below.
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Answer : x = 0 or 2√7 or -2√7
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