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NARA [144]
3 years ago
13

Z+(z-6)-2=-10 how do you solve this

Mathematics
1 answer:
umka21 [38]3 years ago
5 0
Combine like terms
2z-8=-10

Then add 8 to both sides
2z=-2

Then divide both sides by 2
z=-1

Final answer: z=-1
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An Xbox one that costs $525 is discounted 15% for a sale. What is the new discounted price of the xbox one
Vilka [71]

Answer:

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
HELP 30 POINTS!!!!!
Tamiku [17]

by pythagorean formula, the last side is √(61)

by cos rule

cos A

=  \frac{ {6}^{2}  + 61 -  {5}^{2} }{2 \times 6 \times  \sqrt{61} }  \\  =  \frac{72}{12 \sqrt{61} }   \\  =  \frac{6}{ \sqrt{61} }

A = 39.81

5 0
3 years ago
If a polynomial function f(x) has roots 6 and square root of 5, what must also be a root of f(x)?
ivolga24 [154]

Answer:

-\sqrt{5}

Step-by-step explanation:

A root with square root or under root is only obtained when we take the square root of both sides. Remember that when we take a square root, there are two possible answers:

  • One answer with positive square root
  • One answer with negative square root

For example, for the equation:

x^{2}=3

If we take the square root of both sides, the answers will be:

x=\sqrt{3} \text{ or } x= -\sqrt{3}

Only getting one solution with square root is not possible. Solutions with square root always occur in pairs.

For given case, the roots are 6 and \sqrt{5}. Therefore, the 3rd root of the polynomial function f(x) had to be -\sqrt{5}

It seems you made error while writing option B, it should be - square root of 5.

4 0
3 years ago
All questions to be solved using linear combination.
monitta
1)
I:x-y=-7
II:x+y=7

add both equations together to eliminate y:
x-y+(x+y)=-7+7
2x=0
x=0

insert x=0 into II:
0+y=7
y=7

the solution is (0,7)

2)
I: 3x+y=4
II: 2x+y=5

add I+(-1*II) together to eliminate y:
3x+y+(-2x-y)=4+(-5)
x=-1

insert x=-1 into I:
3*-1+y=4
y=7

the solution is (-1,7)

3)

I: 2e-3f=-9
II: e+3f=18

add both equations together to eliminate f:
2e-3f+(e+3f)=-9+18
3e=9
e=3

insert e=3 into I:
2*3-3f=-9
-3f=-9-6
-3f=-15
3f=15
f=5

the solution is (3,5)

4)
I: 3d-e=7
II: d+e=5

add both equations together to eliminate e:
3d-e+(d+e)=7+5
4d=12
d=3

insert d=3 into II:
3+e=5
e=2

the solution is (3,2)

5)
I: 8x+y=14
II: 3x+y=4

add I+(-1*II) together to eliminate y
8x+y+(-3x-y)=14-4
5x=10
x=2

insert x=2 into II:
3*2+y=4
y=4-6
y=-2

the solution is (2,-2)
8 0
3 years ago
Lucy is going to rent a truck for one day. There are two companies she can choose from, and they have the following prices
hram777 [196]

Answer: Any amount of milage more than 30

Step-by-step explanation: You can write an equation to compare the relationship between the costs that looks like:

102<75+0.9m

27=0.9m

m=30

4 0
2 years ago
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