All categories

3 years ago

Is 22 over 7 a repeating decimal?

Mathematics

2 answers:

Oduvanchick [21]3 years ago

8 0

3.142857142857143 that's the answer. I hope this helps.
I think it's not a repeating decimal

Snezhnost [94]3 years ago

7 0

No because it is not in decimal repeating form.

You might be interested in

If there are 16 red bobbles for every 2 green dandees, how many red bobbles are there in 20 green dandees?

kvasek [131]

Answer:

160

Step-by-step explanation:

20 / 2 = 10

10 * 16 = 160

8 0

3 years ago

Does (-1, 2), (1, 1),( 1 -1), (2,1), (4,2) represent y as a function

Paha777 [63]

No. A function maps one input to exactly one output. The given relation maps 1 to both 1 and -1, as indicated by the pairs (1, 1) and (1, -1).

8 0

2 years ago

Please answer this correctly

viva [34]

Answer:

2/5

Step-by-step explanation:

Let's find the probability of each condition first.

For P(4), there is only one option: 4. This is 1 out of 5.

For P(even), this includes 4 and 6. However, we already had 4 from our last condition so we can remove this option. This is again 1 out of 5.

Adding them together, we will get 2/5.

The answer is 2/5

3 0

3 years ago

Help me plz jdjdrjiejdncfjficmdmkwkefjvnfjeje

Oxana [17]

Answer:

-1 5/36

Step-by-step explanation:

8 0

3 years ago

Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms

miv72 [106K]

Hint :-

Break the given sequence into two parts .
Notice the terms at gap of one term beginning from the first term .They are like $\dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ . Next term is obtained by multiplying half to the previous term .
Notice the terms beginning from 2nd term , $4,7,10,13$ . Next term is obtained by adding 3 to the previous term .

Solution :- 

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

$\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ .

We can see that this is in Geometric Progression where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

$\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]$

Notice the term $\dfrac{1}{2^{25}}$ will be too small , so we can neglect it and take its approximation as 0 .

$\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]$

$\\\implies \boxed{ S_1 \approx 1 }$

$\rule{200}2$

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

$\implies S_2=\dfrac{n}{2}[2a + (n-1)d]$

Substitute ,

$\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}$

Hence sum = 908 + 1 = 909

7 0

3 years ago