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Angelina_Jolie [31]
3 years ago
14

What implications does the period of infectiousness have for the control of transmission of these diseases? How are chronic earn

ers of Typhoid and Hepatitis B managed?
Biology
1 answer:
marishachu [46]3 years ago
5 0

Answer:

The implications are epidemies, risk factors and disease burden.

When it comes to Typhoid, the cronic earners are treated with prescribed antibiotics, changes in sanitary habits and blood testing.

When it comes to hepatitis b, the cronic earners are treated with prescribed antivirals,  blood tests, liver ultrasound and biopsy.

Explanation:

<em>Epidemies can occur because the sick population, might not be aware and contaminate the other amount who is not infected. That is the reason why the chronic earners must take the prescribed antibiotics for as long as the physician has prescribed, they must incorporate healthy sanitary habits like washing their hands with soap after using the bathroom, not preparing or serving food to other people. Because these actions will prevent others from getting the illness. And finally, they must get tested  so that the doctor can ensure that no Salmonella Typhi bacteria remain in their body. The best way to avoid Typhoid is by vaccine.</em>

<em>Hepatitis B epidemies, risk factors and disease burden happens when the chronic earner use illegal injected drugs and share the niddle, have unprotected sex with multiple partners, receive kidney dialysis or live with someone who has hepatitis B. So the best way of managing these patients is by lifetime treatment, which means that they will take antiviral medications, interferon injections or have a liver transplant. </em>

<em>The best way of preventing the hepatitis B is by vaccine, safe sex and no drugs.</em>

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Consider a locus with two alleles - B and b. B is dominant, while b is recessive. There is no mutation. B has a selective advant
Marat540 [252]

Answer:

0.09

Explanation:

<h3><u>Before selection</u></h3>

Total number in population = 1000

Genotype frequencies

Genotype frequency of BB = 500/1000 = 0.5

Genotype frequency of Bb = 250/1000 = 0.25

Genotype frequency of bb = 250/1000 = 0.25

Allele frequencies

Allele frequency of B = BB genotype frequency + half of the Bb genotype frequency = 0.5 + (0.25/2) = 0.625

Allele frequency of b = bb genotype frequency + half of the Bb genotype frequency = 0.25 + (0.25/2) = 0.375

<h3><u>After selection</u></h3>

We are told that after selection, the genotype frequency of bb is changed as they become 50% less fit. This means the frequency of bb individuals changes from 250 to 125 individuals (50% reduction).

Now the total number of individuals is 500 + 125 + 250 = 875.

Genotype frequencies

Genotype frequency of BB = 500/875 = 0.57

Genotype frequency of Bb = 250/875 = 0.29

Genotype frequency of bb = 125/875 = 0.14

Allele frequencies

Allele frequency of B = BB genotype frequency + half of the Bb genotype frequency = 0.57 + (0.29/2) = 0.715

Allele frequency of b = bb genotype frequency + half of the Bb genotype frequency = 0.14 + (0.29/2) = 0.285

<h3><u>Change in frequency of B after 1 generation</u></h3>

0.715 - 0.625 = 0.09

7 0
2 years ago
Describe which factors of an ecosystem are not part of a community.
sweet [91]

Answer:

The abiotic factors include water, air, rocks, and sunlight are not part of a community.

5 0
2 years ago
Which of the following describes the process of glycolysis? See Concept 9.2 (Page 170) View Available Hint(s) Which of the follo
Paul [167]

Answer:

It represents the first stage in the chemical oxidation of glucose by a cell.

Explanation:

Glycolysis is the first stage of oxidation of glucose by the process of cellular respiration. Glycolysis includes the breakdown of one molecule of glucose into two molecules of pyruvate. Substrate level phosphorylation forms net 2 ATP molecules and the redox reactions of glycolysis uses NAD+ as an electron acceptor resulting in the formation of 2 NADH.

Therefore, one molecule of glucose obtains 2 pyruvate molecules, 2ATP and 2 NADH by glycolysis. The fate of pyruvate depends on the availability of oxygen. Citric acid cycle and oxidative phosphorylation are the next two stages of aerobic cellular respiration.

8 0
3 years ago
Levene made which contribution to our understanding of DNA structure? a. He determined that the nucleus contains DNA. b. He dete
Stels [109]

Answer:

The correct answer is  b. He determined that DNA contains four nitrogenous bases.

Explanation:

Levene was an American biochemist who studied the structure of DNA in the early 1900s and in 1920 he found that DNA consists of four nitrogenous bases that are Adenine, Guanine, Thymine, Cytosine.

He also found deoxyribose sugar and phosphate group and said that nucleotide is the basic unit of DNA which contains a ribose sugar with attached nitrogenous base and phosphate group.

He also concludes that an equal amount of adenine, guanine, thymine, and cytosine makes the DNA which is now known as tetranucleotide hypothesis. So the correct answer is b. He determined that DNA contains four nitrogenous bases.  

8 0
3 years ago
Introduced invasive species like the Asian citrus psyllid is dangerous because
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Answer: D-All of the above
6 0
3 years ago
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