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ipn [44]
2 years ago
11

Why does the author compare self-deception to a drug in paragraph 6?

Biology
1 answer:
yulyashka [42]2 years ago
5 0

Answer: B  to show that drugs and self-deception can cause someone to ignore reality.

<h3>Ignore reality</h3><h3 />

There are many ways to escape reality, drugs being one of them. Every addiction, that is, every excess, betrays the presence of something behind it and keeps it alive. What sustains the addiction? The fear of facing reality, its own and collective. You run away from reality because you feel unable to sustain it. Without upholding the vision of truth, it is not possible to transform what is not good. Many stop at this first stage:

  • they can't stand to know
  • see and face the harsh and raw reality
  • and escape to an inner fantasy world nourished by a drug, a habit or a belief...

For anything that allows them to remain protected from sight of the real perceived as horrendous. The flight from the facts is an indication of emotional weakness, as you cannot bear the emotion of seeing the tragedy, but it is also synonymous with mental weakness, as you cannot think and process it, the tragedy. Brain and heart flee from reality and, thus, the individual remains in a state of minority. It is for the adult, that is, for the mature person, to know how to deal with What It Is. Therefore, behind every addiction there is an infantile condition structured around beliefs, rationalizations and "beliefs".

with this, we can say that the author wanted to compare how drugs and self-delusion can make someone ignore reality.

learn more brainly.com/question/9567565?referrer=searchResults

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a) The correct answer is 1/2 or 0.5

Cystic fibrosis is a recessive disorder and her sibling has a disease but none of the parents had it. Thus, each of the parents must be the carrier of the disease, that is, both of them must be heterzygous.

So, if we cross Cc x Cc, it results in the genotype ratio of 1 (CC) : 2 (Cc) : 1 (cc)

Thus, 2 out of 4 would be the carrier of the disease.

b) 1/16

The probability of female to the carrier is 1/2

Same is the case with male partner due to the probability that he would be the carrier is 1/2

If both are carrier then, there is only 1/4 chances that the offspring will have the disease (as per cross shown above).

Now, the probability that the offspring will have the disease = product of all the above probabilities. (The probability of occurrence of two independent events is equal to the product of their individual probabilities).

So, \frac{1}{2}x\frac{1}{2}x\frac{1}{4} = \frac{1}{16}

c) 1/8

The probability of female to be the carrier is 1/2

The probability male to be the carrier is 1/2

If both are carrier then, there is only 2/4 chances that the offspring will be the carrier of the disease (as per cross shown above).

Now, the probability that the offspring will be the carrier = product of all the above probabilities. (The probability of occurrence of two independent events is equal to the product of their individual probabilities).

\frac{1}{2}x\frac{1}{2}x\frac{2}{4} = \frac{1}{8}

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