Answer:
The mistake stems from the assumption that angle dab and abc are both 90 and ad = bc and that the perpendicular bisector of dc is different from the perpendicular bisector to ab because they are the same and abcd is a rectangle.
Step-by-step explanation:
If ∡dab = ∡abc and side ab is equal to side bc which are opposite sides, ten then ab is parallel to bc which means the quadrilateral is parallelogram. Also since two angles of the four angles of the parallelogram are 90 degrees then the parallelogram is a rectangle.
The bisector of one side of a rectangle will also bisect the opposite side of the rectangle. Therefore the bisector of dc is the same as the bisector of ab and it meets ab at the midpoint of ab. Therefore p is now at the midpoint of ab and there are no triangles pad and pbc.
Step-by-step explanation:
4:16
No it's ok no need to thank me, it's my duty to help someone like you
2/3x-1=9
+1 +1
2/3x=10
x=10 x 3/2
x=15
Let 
be the length and 
be the width of the rectangle.
Given perimeter of the rectangle
Area of the rectangle is
Also length is 5 more than twice its width,
From the above equations
Now 
The dimensions of the rectangle are length 
, and width 
.
