In ΔBCD, the measure of ∠D=90°, BD = 63, CB = 65, and DC = 16. What ratio represents the cosine of ∠B?

Mathematics

1 answer:

wariber [46]3 years ago

4 0

Answer:

$Cos \angle B=\frac{63}{13}$

Step-by-step explanation:

-Given that ΔBCD is a right triangle with ∠D=90° as in the attached figure.

-The ratio of Cos of ∠B can be obtained using the right triangle identities:

$Cos \ \theta=\frac{Adjacent}{Hypotenuse}\\\\Cos \ B=\frac{63}{16}$

Hence, the cosine of ∠B can be represented by the ratios $Cos \angle B=\frac{63}{13}$

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