Answer:
3
Step-by-step explanation:
Calculate the distance using the distance formula
d = 
with (x₁, y₁ ) = (- 9, 8) and (x₂, y₂ ) = (- 3, - 1)
d = 
= 
= 
= 
= 
= 
=
× 
= 3
The standard size of diplomas are 11x14''
Law Schools or Medical Schools are bigger for colleges.
If the annual rate in 10 years has the same quadralaterical value the answer would be 47.9 but we can make sure our answer is correct
what we know:
The cost changed in 10 years to 23.95
if the cost changed another 10 years it would be another 23.95, 23.95+23.95=47.9 Which is our answer pls mark brainliest
The answer is 138 million.
Step 1. Calculate the growth rate.
Step 2. Calculate the population number in 2014.
We will use the formula for exponential growth:
A = P * eⁿˣ
where:
A - the final amount (value)
P - the initial amount (value)
e - the mathematical constant (e ≈ 2.72)
n - the growth rate
x - the time
Step 1:
A = 120 million = 120 000 000
P = 114 million = 114 000 000
n = ?
x = 1997 - 1991 = 6
Therefore:

Logarithm both sides of the equation:

Step 2:
Now when we know the growth rate, it is easy to estimate the population in 2014
A = ?
P = 120 000 000
n = 0.0083
t = 2014 - 1997 = 17

Thus, the population will be 138 million in 2014