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3 years ago

Dolores spent $13.00 of the $20.00 in her wallet. Which decimal represents the fraction of the $20.00 Dolores spent?

Mathematics

1 answer:

ehidna [41]3 years ago

8 0

Question is Incomplete; Complete question is given below;

Dolores spent $13.00 of the $20.00 in her wallet. Which decimal represents the fraction of the dollars Dolores spent?

0.35

0.13

0.07

0.65

Answer:

0.65

Step-by-step explanation:

Given:

Money in her wallet = $20.00

Money Spent = $13.00

We need to find the decimal representation of the fraction of the dollars Dolores spent.

Solution:

To find the decimal representation of the fraction of the dollars Dolores spent we will Divide Money Spent by Dolores with the Total money he had in her wallet.

framing in equation form we get;

decimal representation of the dollars Dolores spent = $\frac{13}{20} =0.65$

Hence The decimal representation of the fraction of the dollars Dolores spent is 0.65.

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MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

Then, the minimum point of this function is (3,1) and it corresponds to (A)

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

Then, the minimum point of this function is (0,1) and it corresponds to (C)

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

Then, the minimum point of this function is (2,3) and it corresponds to (B)

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

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Then, the minimum point of this function is (2,-2) and it corresponds to (D)

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3 years ago

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victus00 [196]

Answer:

a) 0.9964

b) 0.3040

Step-by-step explanation:

Given data:

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Total number of sample = 100

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P(x<370000) = P(Z<2.689)

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FROM NORMAL DISTRIBUTION TABLE Z VALUE FOR

$P(Z\leq 2.133) = 0.9836$

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lutik1710 [3]

Answer:

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3 years ago

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Rufina [12.5K]

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