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2 years ago

9

A globe has a diameter of 22 in. What is the best approximation for the volume of this globe?

1 answer:

Karolina [17]2 years ago

8 0

<span>Sphere Volume = </span><span> <span> <span>( <span>π <span>• d³) / 6
Sphere Volume = (3.14159265 * 22^3 / 6)
</span></span></span></span></span>
Sphere Volume = <span> <span> <span> 5,575.2797

</span></span></span>It seems they used PI = 3.14 because then the answer is:
<span> <span> <span> 5,572.45

</span></span></span>

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Suppose the length and width of the rectangle are doubled. What effect would this have on the area? Justify your answer

Marta_Voda [28]

Answer:

the area would be 4 times

Step-by-step explanation:

4* 17 = 68

8* 34 = 272

272/68= 4

6 0

2 years ago

What is the distance between the lines y = 2x and y = 2x+5? Round your answer to the nearest tenth.

Ilia_Sergeevich [38]

The distance between both lines is 2.24 units

Step-by-step explanation:

There is no straight method to find the distance between two lines. The distance can be found out by finding a point on one line and then finding the distance of that point from the other line. The y-coordinate of point is obtained by putting any value of x in equation . The x and y combined give us the point.

Given

$y=2x\\Putting\ x=1\\y=2(1)\\y=2\\So, the\ point\ on\ y=2x\ is\ (1,2)$

We have to find the distance of this point from y=2x+5

$y=2x+5\\Subtracting\ y\ from\ both\ sides\\y-y=2x+5-y\\2x-y+5=0$

The formula for finding distance of a point (x,y) from a line is:

$d=\frac{|Ax+By+C|}{\sqrt{A^2+B^2}}$

A=2

B=-1

C=5

Putting the values in the formula

$d=\frac{|(2)(1)+(-1)(2)+5|}{\sqrt{(2)^2+(-1)^2}}\\d=\frac{|2-2+5|}{\sqrt{4+1}}\\d=\frac{|5|}{\sqrt{5}}\\d=\frac{5}{\sqrt{5}}\\d=2.236\ units$

Rounding off will give: 2.24 units

The distance between both lines is 2.24 units

Keywords: Equations of lines

Learn more about distance in lines at:

#LearnwithBrainly

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2 years ago

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Marysya12 [62]

The complete square will be $(x-3)^{2}$ = 3

Step-by-step explanation:

Given,

$2x^{2} -12x+12=0$

or, $x^{2} -6x+6=0$ [ by eliminating 2 from both the sides]

To make it square

$x^{2} -6x+6=0$

or, $x^{2} -2xX3+9-9+6=0$ [ $(a+b)^{2}=a^{2} +2ab+b^{2}$

or, $(x-3)^{2}$ = 9-6

or, $(x-3)^{2}$ = 3

Hence the correct option is B

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2 years ago

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mars1129 [50]

Answer:

Choice C

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the domain is the input values, or the x values

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3 years ago

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