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Vladimir [108]
3 years ago
9

A globe has a diameter of 22 in. What is the best approximation for the volume of this globe?

Mathematics
1 answer:
Karolina [17]3 years ago
8 0
<span>Sphere Volume   = </span><span> <span> <span>( <span>π   <span>• d³) / 6
Sphere Volume = (3.14159265 * 22^3 / 6)
</span></span></span></span></span>
Sphere Volume = <span> <span> <span> 5,575.2797

</span></span></span>It seems they used PI = 3.14 because then the answer is:
<span> <span> <span> 5,572.45


</span></span></span>
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Pepsi [2]

Answer: then what a bad man

Step-by-step explanation:

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3 years ago
The mean salary of people living in a certain city is $37500 with a standard deviation of $1561. a sample of 33 people is select
Murrr4er [49]
The probability is 0.9671.

The z-score for this is given by

z = (x - μ)/(σ/√n)
z = (38000-37500)/(1561/(√33)) = 1.84.

Using a z-table (http://www.z-table.com) we see that the area under the curve to the left of, less than, this is 0.9671.
8 0
3 years ago
Jonathan found a strange piece of metal. He took it to a science lab and found that the metal is 37.5% gold and 62.5% nickel. Wh
ollegr [7]

Answer:

This ratio is 0.6.

Step-by-step explanation:

This ratio is:

gold      37.5%

-------- = ----------- = -0.6

nickel     62.5%

5 0
2 years ago
A national survey of companies included a question that asked whether the company had at least one bilingual telephone operator.
nirvana33 [79]

Answer:

The first option is correct. Option A is correct.

LCL = 0.270, and UCL = 0.397

80% Confidence interval = (0.270, 0.397)

Step-by-step explanation:

The data for Y and N for the 90 companies is attached to this solution provided.

Y represents companies with at least 1 bilingual operator and N represents companies with no bilingual operator.

The number of Y in the data = 30

Hence, sample proportion of companies with at least one bilingual operator = (30/90) = 0.3333

Confidence Interval for the population proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample proportion) ± (Margin of error)

Sample proportion = 0.3333

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error)

Critical value at 80% confidence level for sample size of 90 is obtained from the z-tables.

Critical value = 1.280

Standard error of the mean = σₓ = √[p(1-p)/n]

p = sample proportion

n = sample size = 90

σₓ = √[0.3333×0.6667)/90] = 0.0496891568 = 0.04969

80% Confidence Interval = (Sample proportion) ± [(Critical value) × (standard Error)]

CI = 0.3333 ± (1.28 × 0.04969)

CI = 0.3333 ± 0.0636021207

80% CI = (0.2696978793, 0.3969021207)

80% Confidence interval = (0.270, 0.397)

Hope this Helps!!!

3 0
3 years ago
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mote1985 [20]

Answer:

97

Step-by-step explanation:

3 0
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