Draw the line 3x + y = 10 .[it passes by (0,10) and (-10/3,0)
Draw the line y=x [it passes by (0,0), (1,1), (2,2) etc]
Then the solution is the points with integer x and y, that belong to the segment of the line 3x +y = 10 between the x-axis and the line y=x. Those points are (1,7) , (2,4), (3, 1).
The <span>perpendicular bisectors of the sides of a right triangle intersect on the triangle. The correct option among all the options that are given in the question is the first option or option "a". I hope that this is the answer that you were looking for and it has actually come to your help.</span>
