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NISA [10]
3 years ago
6

The high temperature for the day was 77 while the low was 52. What is the difference between the high and low temperature for th

e day? PLS ANSWER
Mathematics
2 answers:
grin007 [14]3 years ago
4 0

Answer:

25

Step-by-step explanation:

High = 77

Low = 52

Subtract to find difference

High - Low

77 - 52

25

cluponka [151]3 years ago
3 0

Answer:

25 degrees

Step-by-step explanation:

We need to set up a difference. The high is 77 and the low is 52, so let's subtract 52 from 77:

   77

-   52

______

From the rightmost column, we have 7 - 2, which equals 5. So, put 5 there:

   77

-   52

______

      5

Now, look at the left column. We have 7 - 5, which equals 2. So put 2 there:

   77

-   52

______

   25

Thus, the answer is 25 degrees.

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A file that is 278 megabytes is being downloaded. If the download is 19.9% complete, how many megabytes have been downloaded? Ro
noname [10]

Answer:

55.3

Step-by-step explanation:

19.9% of 278 = 55.322

55.322 rounded to the nearest tenth = 55.3

8 0
3 years ago
If f(x)=x+3 and g(x)= x^2 -4 find the expression for g(f(x))
Maksim231197 [3]

Answer:g(f(x))= x^2 +6x+5

Step-by-step explanation:

g(f(x))= x^2 -4

g(f(x))= (x+3)^2 -4

g(f(x))= (x+3)(x+3) -4

g(f(x))= x^2 +6x+9-4

g(f(x))= x^2 +6x+5

4 0
3 years ago
A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.
Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}

6 0
3 years ago
A local coffee shop serves 2/9 as many customers as a shop run by a national coffee chain. The shop run by the chain serves 502
aleksklad [387]

Answer:

116

Step-by-step explanation:

502/9*2

About 57.8*2

115.6

Round up to 116

The local shop serves about 116 customers a day.

8 0
3 years ago
Which congruent theorem can be used to prove..
hjlf

Answer:

Two angles and the non-included side of one triangle are congruent to the corresponding parts of another triangle. Which congruence theorem can be used to prove that the triangles are congruent? Two sides and the included angle of one triangle are congruent to the corresponding parts of another triangle.

5 0
3 years ago
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