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defon
3 years ago
11

Show all steps please

Mathematics
1 answer:
OLga [1]3 years ago
6 0
9-8x\geq0\ \ \ |subtract\ 9\ from\ both\ sides\\\\-8x\geq-9\ \ \ \ |change\ signs\\\\8x\leq9\ \ \ \ |divide\ both\ sides\ by\ 8\\\\x\leq9\\\\  |9-8x|=\left\{\begin{array}{ccc}9-8x&for\ x\leq9\\8x-9&for\ x \ \textgreater \  9\end{array}\right

1^o\ x\in(-\infty;\ 9]\to|9-8x|=9-8x\\\\9(9-8x)=2x+3\\81-72x=2x+3\ \ \ \ |subtract\ 81\ from\ both\ sides\\-72x=2x-78\ \ \ \ |subtract\ 2x\ from\ both\ sides\\-74x=-78\ \ \ \ |divide\ both\ sides\ by\ (-74)\\\\x=\dfrac{-78:2}{-74:2}\\\\\boxed{x=\frac{39}{37}}\in(-\infty;\ 9]

2^o\ x\in(9;\ \infty)\to|9-8x|=8x-9\\\\9(8x-9)=2x+3\\72x-81=2x+3\ \ \ \ |add\ 81\ to\ both\ sides\\72x=2x+84\ \ \ \ |subtract\ 2x\ from\ both\ sides\\70x=84\ \ \ \ \ \ |divide\ both\ sides\ by\ 70\\\\x=\dfrac{84:14}{70:14}\\\\x=\dfrac{6}{5}\notin(9;\ \infty)\\\\\\Answer:\boxed{x=\frac{39}{37}}
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tensa zangetsu [6.8K]

Explanation:

First you had to square from both sides of equation form.

(\sqrt{x-6+2})^2=6^2

Then you expanded form.

(\sqrt{x-6+2})^2=x-4

x-4=36

6^2=6*6=36

Solve by equation form.

x-4=36

Add by four from both sides of equation form.

x-4+4=36+4

Simplify.

x=40

Verified solutions.

x=40 \boxed{TRUE}

Final answer: \boxed{x=40}

Hope this helps!

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