For what values of x is x2-36=5x true?
0 -9 and 4
04 and 9
4 and -9
09 and 4
1 answer:
Answer:
x = - 4 and x = 9
Step-by-step explanation:
Given
x² - 36 = 5x ( subtract 5x from both sides )
x² - 5x - 36 = 0
Consider the factors of the constant term (- 36) which sum to give the coefficient of the x- term (- 5)
The factors are - 9 and + 4, since
- 9 × 4 = - 36 and - 9 + 4 = - 5, thus
(x - 9)(x + 4) = 0
Equate each factor to zero and solve for x
x - 9 = 0 ⇒ x = 9
x + 4 = 0 ⇒ x = - 4
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Step-by-step explanation:
Given



Required
Find P(A) and P(B)
We have that:
--- (1)
and
--- (2)
The equations become:
--- (1)

Collect like terms


Make P(A) the subject

--- (2)


Substitute: 
![[0.770 - P(B)] * P(B) = 0.144](https://tex.z-dn.net/?f=%5B0.770%20-%20P%28B%29%5D%20%2A%20P%28B%29%20%3D%200.144)
Open bracket

Represent P(B) with x

Rewrite as:

Expand

Factorize:
![x[x - 0.45] - 0.32[x - 0.45]= 0](https://tex.z-dn.net/?f=x%5Bx%20-%200.45%5D%20-%200.32%5Bx%20-%200.45%5D%3D%200)
Factor out x - 0.45
![[x - 0.32][x - 0.45]= 0](https://tex.z-dn.net/?f=%5Bx%20-%200.32%5D%5Bx%20-%200.45%5D%3D%200)
Split

Solve for x

Recall that:

So, we have:

Recall that:

So, we have:


Since:

Then:

