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telo118 [61]
4 years ago
12

What are the zeros of the polynomial function?

Mathematics
1 answer:
Serga [27]4 years ago
4 0
First compute the discriminant delta:
9^2-4*1*20=1. 
Using the quadratic formula, we get the solutions:
\frac{-9-1}{2} =-5\\ \frac{-9+1}{2}=-4
the solutions are then -4 and -5. 
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3 Which of the following points does not lie
Radda [10]
I’m pretty sure the answer is b but not 100%
8 0
3 years ago
I need it asap plzzz​
densk [106]

Answer:

0.2.34

That is probs the answer for B

4 0
3 years ago
Which expression is not equivalent to −4x3+x2−6x+8?
Gekata [30.6K]

The expression which is not equivalent to the provided expression is expression number 1, x²(-4x+1)-2(3x-4).

<h3>What is the equivalent expression?</h3>

Equivalent expressions are the expression whose result is equal to the original expression, but the way of representation is different.

The expression given in the problem is

f(x)=-4x³+x²-6x+8

The option given as,

  • (1) x² (-4x+1)-2(3x-4)
  • (2) x(-4x²- x + 6) + 8
  • (3) -4x³ + (x - 2)(x - 4)
  • (4) -4(x³ - 2) + x(x - 6)

From the given expression, if we take out <em>x </em>from the first three terms, it looks like option 2.

f(x)=-4x³+x²-6x+8

f(x)=x(-4x²+x-6)+8

From the given expression, if the last three terms factored, it looks like option 3.

f(x)=-4x³+x²-6x+8

f(x)=-4x³+x^2-4x-2x+8

f(x)=-4x³+x(x-4)-2(x-4)

f(x)=-4x³+(x-4)(x-2)

Rearrange the given expression, and make it looks like option 4.

f(x)=-4x³+x²-6x+8

f(x)=-4x²+8+x²-6x

f(x)=-4(x³-2)+x(x-6)

Thus, the expression which is not equivalent to the provided expression is expression number 1, x²(-4x+1)-2(3x-4).

Learn more about the equivalent expression here;

brainly.com/question/2972832

#SPJ1

4 0
2 years ago
Mrs. Robert’s vegetable garden is 6 feet wide and 8 feet long. A drawing of the garden has a scale of 1 inch 2 feet. What is the
RSB [31]

Answer:

Step-by-step explanation:

It’s 24

5 0
3 years ago
Read 2 more answers
Find all the values of x where the tangent line is horizontal.<br> f(x) = 2x^3 + 42x^2 + 270x + 11
WITCHER [35]

Answer:

If I calculated correctly, the tangent line is horizontal where x ≈ -5.3 + 9.3i, and -5.3 - 9.3i

I'm somewhat concerned at having gotten complex numbers, and strongly recommend going through the steps to see if I missed anything.  I checked it myself and don't see any errors.

Step-by-step explanation:

You can do this by taking the derivative of the function and solving for zero:

f(x) = 2x³ + 32x² + 220x + 11

f'(x) = 6x² + 64x + 220

f'(x) = 2(3x² + 32x + 110)

We can't factor that further, so let's do it the long way, starting by letting f'(x) equal zero:

0 = 2(3x² + 32x + 110)

0 = 3x² + 32x + 110

0 = 9x² + 96x + 990

0 = 9x² + 96x + 256 + 734

0 = (3x + 16)² + 734

(3x + 16)² = -734

3x + 16 = ± i√734

3x = -16 ± i√734

x = (-16 ± i√734) / 3

x ≈ (-16 + 27.9i) / 3, and  (16 - 27.9i) / 3

x ≈ -5.3 + 9.3i, and -5.3 - 9.3i

I'm always wary when I end up with complex numbers.  I'd suggest double checking everything here, but I'm fairly certain I did everything correctly.

8 0
3 years ago
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