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3 years ago

15

What is the value of theta for the acute angle in a right triangle?

2 answers:

balu736 [363]3 years ago

5 0

we are given

$sin(\theta)=cos(73)$

we have to find theta

so, firstly we can write sin in terms of cos

$sin(\theta)=cos(90-\theta)$

now, we can set it equal

$cos(90-\theta)=cos(73)$

Since, both sides are cos

so, we can set angles equal

$90-\theta=73$

now, we can solve for theta

we get

$\theta=17$ ..............Answer

Anastasy [175]3 years ago

3 0

Answer: 17

Step-by-step explanation:Took the the 100% ..

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21.77 you can also type that in in the google search bar and your answer will pop up

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$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

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<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

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<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

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$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

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$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

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<h3>Problem 4</h3>

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