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Oliga [24]
4 years ago
9

The second angle in a triangle is five times as large as the first. The third angle is two-thirds as large as the first. What ar

e the angle measurements?
Mathematics
1 answer:
FromTheMoon [43]4 years ago
4 0
The ratio being 1:5:3, you would have to just make those numbers still in that ratio, but they have to add up to 180 degrees.The angles would be 20 degrees, 100 degrees, and 60 degrees.  Hope that helped. :)

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Solve the system of equations<br> 2x+3y=1<br> y=3x+15<br> (___,___)
Allisa [31]
2x + 3y = 1
y = 3x + 15

Get the same variables on each side

3y = 1 - 2x
y = 15 + 3x

Multiply both sides of that second equation by 3 so we can subtract.

3y = 1 - 2x
3y = 45 + 9x

Subtract the equations from each other.

0 = -44 - 11x

Solve.

44 = -11x
-4 = x

Use x in an earlier equation to find y.

y = 3x + 15
y = 3 * -4 +15
y = -12 + 15
y = 3

x = -4, y = 3
3 0
4 years ago
Read 2 more answers
60 percent of what number is 24?
elena-s [515]
The answer is 14.4

Hope it Helps :]

5 0
3 years ago
When you are determining The probability of an event why must the probability be between 0 and 1
slega [8]

The probability of an event cannot be less than 0 because 0 means it's impossible. The probability of an event cannot be more than 1 because 1 means that it's certain that it will happen. That's why the probability must be between 0 and 1.

7 0
4 years ago
If a number is divided by 3 it will be odd true or false
EastWind [94]

Step-by-step explanation:

False

ex. 12 can be divided by 3

but it's even number

6 0
4 years ago
Divide. simplify your answer (2x^4-6x^3+4x^2-3x)*(2x) pls show work
denis23 [38]

Distribute

2x × 2x^4 + 2x × -6x^3 + 2x ×4x^2 + 2x × - 3x

Take out the constants

(2 × 2)xx^4 + 2x × -6x^3 + 2x × 4x^2 + 2x × -3x

Simplify 2 × 2 to 4

4xx^4 + 2x × -6x^3 + 2x × 4x^2 + 2x × -3x

Use Product Rule: x^a x^b = x^a + b

4x^1 + 4 + 2x × -6x^3 + 2x ×4x^2 + 2x × -3x

Simplify 1 + 4 to 5

4x^5 + 2x × -6x^3 + 2x × 4x^2 + 2x × -3x

Take out the constants

4x^5 + (2 × -6)xx^3 + 2x × 4x^2 + 2x × -3x

Simplify 2 × -6 to -12

4x^5 - 12xx^3 + 2x × 4x^2 + 2x × -3x

Use the Product Rule: x^a x^b = x^a + b

4x^5 - 12x^1 + 3 + 2x × 4x^2 + 2x -3x

Simplify 1 + 3 to 4

4x^4 - 12x^4 + 2x ×4x^2 + 2x × -3x

Take out the constants

4x^5 - 12x^4 + (2 × 4)xx^2 + 2x × -3x

Simplify 2 × 4 to 8

4x^5 - 12x^4 + 8xx^2 + 2x × -3x

Use the Product Rule: x^a x^b = x^a + b

4x^5 - 12x^4 + 8x^ 1 + 2 + 2x × -3x

Simplify 1 + 2 to 3

4x^5 - 12x^4 + 8x^3 + 2x × -3x

Take out the constants

4x^5 - 12x^4 + 8x^3 + (2 × -3)xx

Simplify 2 × -3 to -6

4x^5 - 12x^4 + 8x^3 - 6xx

Use the Product Rule: x^a x^b = x^a + b

<u>4x^5 - 12x^4 + 8x^3 - 6x^2</u>

8 0
3 years ago
Read 2 more answers
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