I think( so correct me if i'm wrong).....Using the distance formula... D=Rate x Time, you alter it so that it equals time, since you want to find the number of weeks.
Time = Distance/ rate
SInce you start off at 2 and end up with 5, the total distance is 3 (I subtracted 5-2). And rate is already 12% (this is the iffy part, I'm not sure if you change the 12% in anyway.... but lets move on)
SO Time= 3miles/ 12% which is 1/4 of a week, or possibly.....
Time = 3 miles/ 0.12 which would equal 25 weeks.....
Do they give you these answers?
Answer:
Two possible lengths for the legs A and B are:
B = 1cm
A = 14.97cm
Or:
B = 9cm
A = 12cm
Step-by-step explanation:
For a triangle rectangle, Pythagorean's theorem says that the sum of the squares of the cathetus is equal to the hypotenuse squared.
Then if the two legs of the triangle are A and B, and the hypotenuse is H, we have:
A^2 + B^2 = H^2
If we know that H = 15cm, then:
A^2 + B^2 = (15cm)^2
Now, let's isolate one of the legs:
A = √( (15cm)^2 - B^2)
Now we can just input different values of B there, and then solve the value for the other leg.
Then if we have:
B = 1cm
A = √( (15cm)^2 - (1cm)^2) = 14.97
Then we could have:
B = 1cm
A = 14.97cm
Now let's try with another value of B:
if B = 9cm, then:
A = √( (15cm)^2 - (9cm)^2) = 12 cm
Then we could have:
B = 9cm
A = 12cm
So we just found two possible lengths for the two legs of the triangle.
6 hours
. . . . . . . . . . . . . . . . . . .
Answer:
The dimensions of rectangular fence are 14 feet and 20 feet.
Step-by-step explanation:
We are given the following in the question:
Length of rectangular fence = 14 feet
Width of fence = (14+x) feet
Area of rectangular field = 280 square feet
Area of rectangular field =
Putting the values, we get,
Thus, the dimensions of rectangular fence are 14 feet and 20 feet.
