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Murljashka [212]
3 years ago
12

What is the slope of this line

Mathematics
2 answers:
BaLLatris [955]3 years ago
7 0
Slope=rise/run
basically it is the change in x divided by the change in y
change is x is left to right
change in y is up and down

if we pick 2 points
(1,2) and (2,2)
the chnage in x is 1 and the change in y is 0
slope=0/1=0
the slope is 0
Troyanec [42]3 years ago
4 0
The slope of this line is m=0









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Suppose 1 in 5 (1/5) JWU students own their own car. If four students are randomly selected, what is the probability that all fo
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1/625 = 0.0016

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update, oh sorry, this is about 4 picks and not 5.

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let's assume that the total number of students is large enough that each pick does not change the individual probabilities.

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the probability that all 4 previous picks own a car is the chance of picking the fourth student owning a car AND all 3 previous student picks owning a car.

the probability that all 3 previous picks own a car is the chance of picking the third student owning a car AND all 2 previous student picks owning a car.

the probability that all 2 previous picks own a car is the chance of picking the second student owning a car AND the previous student pick owning a car.

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In order to justify this claim for the Ferengi a sample of 16 coils is taken. For this sample set, the mean warp phase flux is f
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The responses to these question can be defined as follows:

Step-by-step explanation:

n = 16\\\\  \bar{x}= 73.7\\\\\sigma = 12\\\\a = 0.05\ or\  a = 0.10\\\\H_{o} \ : \mu = 68\\\\H_{a} \ : \mu \neq 68\\\\a = 0.05\\\\

critical values =\pm t0.025,15 = \pm 2.131\\\\

(n-1) = 15^{\circ}\\\\a = 0.10\\\\

critical values= \pm t0.05,15 = \pm 1.753\\\\

(n-1) = 15^{\circ}\\\\

Testing the statistic values:

t = \frac{x-\mu_{0}}{ \frac{s}{\sqrt{n}}}\\\\

  = \frac{73.7-68}{(\frac{12}{\sqrt{16}})}\\\\\  = \frac{5.7}{(\frac{12}{4})}\\\\  = \frac{5.7}{(3)}\\\\  = 1.9\\

Test statistic ta = -1.90\ lies

The critical values\pm t_{0.05,15} =\pm 1.753

It is in the region of dismissal. We dismiss the 10% significant null hypothesis.

t_a = 1.90 \\\\df = 15\\\\a = 0.05\\\\p-value = 076831\\\\

P - value is greater than the level of significance a= 0.05  

Null hypothesis we don't reject. At a 95% level, the claim is justified.

t_a = 1.90\\\\ df = 15\\\\  a = 0.10\\\\p-value = 076831\\\\

P - value below the meaning level a = 0.10, we reject the hypothesis null. At a level of 90% the claim is not justified.

3 0
3 years ago
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