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Paul [167]
3 years ago
7

In order to justify this claim for the Ferengi a sample of 16 coils is taken. For this sample set, the mean warp phase flux is f

ound to be 73.7 cochranes with a sample measured standard deviation of 12 cochranes. Is this claim justified at the two-sided 95% or 90% levels? (Derive and define the appropriate values to show true or false for each of the levels. Eg. Is the found mean within the allowed range?)
Mathematics
1 answer:
Kay [80]3 years ago
3 0

Answer:

The responses to these question can be defined as follows:

Step-by-step explanation:

n = 16\\\\  \bar{x}= 73.7\\\\\sigma = 12\\\\a = 0.05\ or\  a = 0.10\\\\H_{o} \ : \mu = 68\\\\H_{a} \ : \mu \neq 68\\\\a = 0.05\\\\

critical values =\pm t0.025,15 = \pm 2.131\\\\

(n-1) = 15^{\circ}\\\\a = 0.10\\\\

critical values= \pm t0.05,15 = \pm 1.753\\\\

(n-1) = 15^{\circ}\\\\

Testing the statistic values:

t = \frac{x-\mu_{0}}{ \frac{s}{\sqrt{n}}}\\\\

  = \frac{73.7-68}{(\frac{12}{\sqrt{16}})}\\\\\  = \frac{5.7}{(\frac{12}{4})}\\\\  = \frac{5.7}{(3)}\\\\  = 1.9\\

Test statistic ta = -1.90\ lies

The critical values\pm t_{0.05,15} =\pm 1.753

It is in the region of dismissal. We dismiss the 10% significant null hypothesis.

t_a = 1.90 \\\\df = 15\\\\a = 0.05\\\\p-value = 076831\\\\

P - value is greater than the level of significance a= 0.05  

Null hypothesis we don't reject. At a 95% level, the claim is justified.

t_a = 1.90\\\\ df = 15\\\\  a = 0.10\\\\p-value = 076831\\\\

P - value below the meaning level a = 0.10, we reject the hypothesis null. At a level of 90% the claim is not justified.

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Roman55 [17]

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Answer:

  C.  (10, 5), (5, 0), (0, 5)

Step-by-step explanation:

In order for the square to have an area of 50 square units, its side lengths must be √50 = 5√2 units long. The only way to get such a length with integer coordinates is for the sides of the square to be themselves the diagonals of a square 5 units on a side.

That is, two of the other vertices of the square must be among ...

  (5±5, 10±5) ⇒ (10, 15), (0, 15), (10, 5), (0, 5)

Only choice C contains two of the vertices on this list.

7 0
3 years ago
A researcher is interested in knowing the average height of the men in a village. To the researcher, the population of interest
Anna11 [10]

Answer:

The population mean height of men in the village is 5.78 feet.

The sample mean height of men in the village is 7.8 feet.

Step-by-step explanation:

It is provided that the researcher's interest is in knowing the average height of the men in a village.

To the researcher, the population of interest is the <em><u>men</u></em><em> </em>in the village, the relevant population data are the <em><u>height of men</u></em> in the village, and the population parameter of interest is the <em><u>mean height of men</u></em>.

It is also provided that there are 590 men in the village, and the sum of their heights is 3,410.2 feet.

Compute the average height as follows:

\bar X_{H}=\frac{3410.2}{590}=5.78\ \text{feet}

Thus, the population mean height of men in the village is 5.78 feet.

It is given that the researcher measured the heights of 18 village men and calculated the average to estimate the average height of all the village men.

The sample for his estimation is <em><u>18 men</u></em>, the relevant sample data are the <em><u>heights of the 18 men</u></em>, and the sample statistic is the <em><u>sample mean height</u></em>.

It is also given that the  sum of the heights of the 18 village men is 104.4 feet.

Compute the average height of the 18 men as follows:

\bar x_{H}=\frac{104.4}{18}=7.8\ \text{feet}

Thus, the sample mean height of men in the village is 7.8 feet.

8 0
3 years ago
The 7 a.m. flight from Dallas to Chicago is on time 75% of the time. Fran created this spinner to simulate the scenario. Fran sp
damaskus [11]

Answer:

Choice C; The flight will be late on one of the three days.

Step-by-step explanation:

The flight is 75% of the time. This means that out of 4 flights, 3 are on time and  the result of Franc's spinner should reflect this fact, i.e his spinner should give 75% probability of flights on time.

Choice A says the flight is on time 0% of the time, This is not true, therefore this is not a correct interpretation of the three spins.

Choice B says the flight is on time 100% of the time, This is not true, therefore this is not a correct interpretation of the three spins.

Choice C says the flight is on time 66% of the time, which is close to 75%. Therefore this choice is close and correct.

Choice D says the flight is on time 30% of the time, This is not true, therefore this is not a correct interpretation of the three spins.

Thus only choice C is correct.

7 0
3 years ago
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RSB [31]
The answer appears to be A. I believe that D is incomplete.<span />
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3 years ago
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kolbaska11 [484]
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p²+44²>250250

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take the square root of both sides:

√p²>+√248314

p> 498.3 or 500 is the number
8 0
3 years ago
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