A.) 7^4x = 10
log base 10 (7^4X) = log base 10 (10)
4x log base 10 (7) = 1
4x (0.8451) = 1
3.3804x = 1
x = 0.2958
b.) ln(2) + ln(4x-1) = 5
ln (2 * 4x-1) = 5
ln (8x-2) = 5
log base (3) (8x-2) = 5
e^5 = 8x-2
e^5+2 = 8x
x = 18.8016
Answer:
first choice
Step-by-step explanation:
make 1/3 and 1/2 a common denominator, which is 6.
1x2
- = 2
-
3x 2 6
1 x 3
- = 3
-
2 x 3 6
now u have 2/6, and 3/6
u subtract 2/6 by 3/6 since ur finding a solution to an inequality. remember to do the opposite sign.
2/6-2/6 = 0 (u cancel that out)
3/6 - 2/6 = 1/6
now u have
q>1/6
since there's no 1/6 the first choice is the most accurate
Let June's age be

Then his father is

The sum of their ages is no less than 77 means,



The youngest age June can be is 11
Answer:
b.
Step-by-step explanation:
15 .12.9the sum of 5 4.3
A
B
C
D
51 squared is 7.14...