First let us convert 0.01 into fraction:

Now we convert 100 and 4 into perfect squares as follows:

Now we use the property of :


Answer:
x=3/2y+3
Step-by-step explanation:
Let's solve for x.
2x−3y=6
Step 1: Add 3y to both sides.
2x−3y+3y=6+3y
2x=3y+6
Step 2: Divide both sides by 2.
2x2=3y+62
x=32y+3
Answer:
Adult=58
Step-by-step explanation:
c=child, a=adult
6.4c+9.7a=1145 equation 1
c+a=149 equation 2
a=149-c modified equation 2 to isolate a
6.4c+9.7(149-c)=1145 substitute value of a from equation 1 into equation 2
6.4c+1445.3-9.7c=1145
-3.3c=-300.3
c=91
solve for a
c+a=149
91+a=149
a=58
Check answer:
6.4c+9.7a=1145
6.4(91)+9.7(58)=1145
582.40+562.60=1145
1145=1145
the first one is true and the second one is false