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OLEGan [10]
3 years ago
11

I need an answer asap

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
3 0

I got \frac{2}{5}m+\frac{-1}{5}

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Whats the answer plz??
Snezhnost [94]

Answer:

C

Step-by-step explanation:

Absolute Value is the distance from 0, so when you have -|22| that means its the absolute value of 22 then add the negative sign so that means it's further from 0 than |-22|.

I hope this will help.

5 0
2 years ago
Find the inverse of the function f f (x )<br><br> equals 9 x + 7
MrMuchimi

<em>Note: Your question seems a little bit ambiguous. So, I am assuming the given function f(x)=9x+7.</em>

<em>Thus, I am solving based on it. It would still clear your concept. </em>

Answer:

The inverse of f(x)=9x+7

  • \frac{x-7}{9}

Step-by-step explanation:

Given the function

f(x)=9 x + 7

A function g is the inverse of function f if for y=f(x), x=g(y)

Replace x with y

x=9y+7

solve for y

9y=x-7

y=\:\frac{x-7}{9}

Therefore,

The inverse of f(x)=9x+7 is:

  • \frac{x-7}{9}

i.e.

\mathrm{Inverse\:of}\:9x+7:\quad \frac{x-7}{9}

6 0
3 years ago
Write the complex number in trigonometric form a+bi. 3(cos270+I sin 270)
Darya [45]
Simply get the value of the angle and distribute away.

\bf 3[cos(270^o)+i~sin(270^o)\implies 3[0+i( -1)]\implies 3-3i
4 0
3 years ago
A segment XD is drawn in rectangle QUAD as shown
grin007 [14]

Answer:

∠XDQ : 41°

∠UXD: 139 °

Step-by-step explanation:

Allow me to rewrite your answer for a better understanding and please have a look at the attached photo.

<em>A segment XD is drawn in rectangle QUAD as shown  below. </em>

<em>What are the measures of ∠XDQ and ∠UXD ? </em>

My answer:

As we can see in the photo, ∠ADX = 49° and ∠ADU =90°

=>  ∠XDQ = ∠ADU - ∠ADX

= 90°  - 49°  = 41°

In the triangle ADX, we can find out the angle of ∠DXA

= 180° - ∠DAX - ∠ADX

= 180° - 90° - 49°

= 41°

=> <em>∠UXD = </em>180° - ∠DXA  (Because UA is a straight line)

=180° - 41°  

= 139 °  

5 0
3 years ago
A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square
kondaur [170]
This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

V = xxy = x^{2}y

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = x^{2}

Surface area of the rectangular sides = 4xy

Therefore, the total area of the cube is:

A = 48 ft^{2} =  x^{2} + 4xy

Isolating the variable y in terms of x:

y =  \frac{48- x^{2} }{4x}

Substituting this value in V:

V =  x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

\frac{dv}{dx} = 48-3x^{2} =0

Solving for x:

x =  \sqrt{\frac{48}{3}} =  \sqrt{16} = 4

Solving for y:

y =  \frac{48- 4^{2} }{(4)(4)} = 2

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width =  4 ft
Height = 2 ft

And its volume is:

V = (4^{2} )(2) = 32 ft^{3}

8 0
3 years ago
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