All categories

3 years ago

I need an answer asap

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

3 0

I got $\frac{2}{5}m+\frac{-1}{5}$

You might be interested in

What’s the measures of the indicated angles

34kurt

Answer:

hope the attached picture gives the answers

6 0

3 years ago

Find the distance BF for the points B(1,-1) and F(-3,5)

Nadusha1986 [10]

Use the distance formula:
 $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Plug in the given coordinates:
 $\sqrt{(-3-1)^2 + (5-(-1))^2}$

Simplify:
 $\sqrt{(-3-1)^2 + (5+1))^2}$

$\sqrt{-4^2+ 6^2}$

$\sqrt{16+36}$

$\sqrt{52}$
You can leave it as: $\sqrt{52}$ or in decimal form as: 7.2

6 0

3 years ago

there are two boxes. in the first box there are 7 cards numbered from 1 tp 7 the second box also contains 7 cards from 1-7 pick

mrs_skeptik [129]

Answer:

$\frac{6}{49}$

Step-by-step explanation:

GIVEN: There are two boxes. in the first box there are $7$ cards numbered from $1$ to $7$ the second box also contains $7$ cards from $1-7$ pick one card from each box.

TO FIND: probability that the sum of the two two cards is at least $12$ .

SOLUTION:

sample case such that sum of cards is $12$ : $(5,7),(7,5),(6,6)$

sample case such that sum of cards is $13$ : $(7,6),(6,7)$

sample case such that sum of cards is $14$ : $(7,7)$

Total sample case such that sum is atleast $12$ $=6$

Total sample cases $=49$

probability that the sum of the two two cards is at least $12$ $=\frac{\text{sample case in which sum is atleast 12}}{\text{total sample cases}}$

$=\frac{6}{49}$

probability that the sum of the two two cards is at least $12$ is $\frac{6}{49}$

8 0

3 years ago

The sum of the digits in a 2 digit number is 5. If the number is subtracted by 9 then the digits will be reversed. Find the numb

emmasim [6.3K]

Answer:

Let ten's place digit =x and unit place digit =y

Number=10x+y

x+y=5 ...(i)

10x+y−9=10y+x

9x−9y=9x−y=1 ...(ii)

from (i) and (ii) we get,

x=3,y=2

∴Number=10×3+2=32.

Step-by-step explanation:

Hope it helps!

4 0

3 years ago

Sum of 1+3+5+7+...+997

PilotLPTM [1.2K]

1 + 3 + 5 + 7 + ... + 997

1, 3, 7, ... , 997 are terms of an arithmetic sequence

$a_1=1;\ a_2=3;\ ...;\ a_n=997\\\\d=a_2-a_1\to d=3-1=2\\\\a_n=a_1+(n-1)d\\\\subtitute\\\\997=1+(n-1)\cdot2\\977=1+2n-2\\977=2n-1\ \ \ \ |add\ 1\ to\ both\ sides\\2n=998\ \ \ \ |divide\ both\ sides\ by\ 2\\n=499\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\subtitute:\ a_1=1;\ a_n=997;\ n=499\\\\S_{499}=\dfrac{1+997}{2}\cdot499=\dfrac{998}{2}\cdot499=499\cdot499=249,001$

Answer: 1 + 3 + 5 + 7 + ... + 997 = 249,001.

4 0

3 years ago