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3 years ago

Will reward the best answer brainliest.

1 answer:

3 0

No solution

to eliminate a variable you need to multiple the second equation by either a 3 and then subtract the two equations or by a -3 and add the two equations.
after changing it, instead of eliminating only one variable, both variables are eliminated and there is no solution

i hope this makes sense, not sure how else to explain

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How to Simplify. (–21 × 3) + (15 ÷ –3)

vladimir2022 [97]

Answer:

-68 is your answer

Step-by-step explanation:

Remember to follow PEMDAS (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction)

First, solve each parenthesis

(-21 x 3) = -63

(15/-3) = -5

Next, add

(-63) + (-5) = -63 - 5 = -68

-68 is your answer

5 0

3 years ago

Find all the factor pairs for 84 and complete the equations.

VMariaS [17]

1. 84 = 1 x 84

2. 84 = 2 x 42

3. 84 = 3 x 28

4. 84 = 4 x 21

5. 84 = 6 x 14

6. 85 = 7 x 12

Hope this helps!

5 0

3 years ago

What is the volume of the can below? Use Pi = 3.14 and round your answer to the nearest tenth. A cylinder with height 96 millime

Serga [27]

Answer:

$328,268 mm^3$

Step-by-step explanation:

The can in this problem has a cylindrical shape. The volume of a cylinder can be calculated with the following formula:

$V=\pi r^2 h$

where

r is the radius of the base of the cylinder

h is the height of the cylinder

In this problem we have:

h = 96 mm is the height of the can

d = 66 mm is the diameter of the can

So the radius of its base is

$r=\frac{d}{2}=\frac{66}{2}=33 mm$

And therefore, the volume of the can is:

$V=\pi (33)^2 (96)=328,268 mm^3$

7 0

3 years ago

Read 2 more answers

Evaluate the indicated function for f(x) = x2 − 1 and g(x) = x − 2 algebraically. If possible, use a graphing utility to verify

Maru [420]

(F-g)(-2) is the answer

5 0

3 years ago

1. Determine a rule that could be used to explain how the volume of a

Eva8 [605]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- We will use the basic formulas for calculating the volumes of two solid bodies.

- The volume of a cylinder ( V_l ) is represented by:

$V_c = \pi *r^2*h$

- Similarly, the volume of cone ( V_c ) is represented by:

$V_c = \frac{1}{3}*\pi *r^2 * h$

Where,

r : The radius of cylinder / radius of circular base of the cone

h : The height of the cylinder / cone

- We will investigate the correlation between the volume of each of the two bodies wit the radius ( r ). We will assume that the height of cylinder/cone as a constant.

- We will represent a proportionality of Volume ( V ) with respect to ( r ):

$V = C*r^2$

Where,

C: The constant of proportionality

- Hence the proportional relation is expressed as:

V∝ r^2

- The volume ( V ) is proportional to the square of the radius. Now we will see the effect of multiplying the radius ( r ) with a positive number ( a ) on the volume of either of the two bodies:

$V = C*(a*r)^2\\\\V = C*a^2*r^2$

- Hence, we see a general rule frm above relation that multiplying the result by square of the multiple ( a^2 ) will give us the equivalent result as multiplying a multiple ( a ) with radius ( r ).

- Hence, the relations for each of the two bodies becomes:

$V = (\frac{1}{3} \pi *r^2*h)*a^2$

$V = ( \pi *r^2*h)*a^2$

8 0

3 years ago