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4 years ago

If 2(x - 5) + 3(x - 5) = 10, what is the value of x - 5?

Mathematics

2 answers:

Darya [45]4 years ago

6 0

Answer:

x = 2

Step-by-step explanation:

2x - 10 + 3x - 15 = 10

5x - 25 = 10

5x = 35

x = 7

7 - 5 = 2

Anestetic [448]4 years ago

4 0

Answer:

x-5 =7-5 =2

Step-by-step explanation:

2(x-5)+3(x-5)=10

2x-10+3x-15=10

-25+5x=10

+25 both sides

5x=35

x=7

7-5=2

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What is 5(y-2)-2=2(y+1)-5? Solve for y and show your work please.

Inessa [10]

Answer:

y = 3

Step-by-step explanation:

Let's start with the left side of the equation.

5(y-2)-2= 2(y+1)-5

5y-10-2= 2(y+1)-5

Now let's solve the right side

5y-10-2= 2y+2-5

5y-12= 2y-3

-2y -2y

3y-12=-3

+12 +12

3y = 9

3y/3 = 9/3

y = 3

hope this helps!

4 0

3 years ago

Find the slope of the line going through the points (0, -5) and (-2,1)

kvasek [131]

Answer:

$\displaystyle m=-3$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Slope Formula: $\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Point (0, -5)

Point (-2, 1)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Substitute in points [Slope Formula]: $\displaystyle m=\frac{-5-1}{0--2}$
[Fraction - Denominator] Simplify: $\displaystyle m=\frac{-5-1}{0+2}$
[Fraction - Numerator] Subtract: $\displaystyle m=\frac{-6}{0+2}$
[Fraction - Denominator] Add: $\displaystyle m=\frac{-6}{2}$
[Fraction] Divide: $\displaystyle m=-3$

8 0

3 years ago

Solve the following equation. X cubed minus 6X squared plus 6X equals zero

anyanavicka [17]

We have to solve this equation:

$x^3-6x^2+6x=0$

Third degree polynomials like this one are not easily solved, but this one has a root at x = 0. The let us factorize this polynomial as x times a second degree polynomial:

$\begin{gathered} x^3-6x^2+6x=0 \\ x(x^2-6x+6)=0 \end{gathered}$

Now we can find the roots of the quadratic polynomial as:

$\begin{gathered} x=\frac{-(-6)\pm\sqrt[]{(-6)^2-4\cdot1\cdot6}}{2\cdot1} \\ x=\frac{6\pm\sqrt[]{36-24}}{2} \\ x=\frac{6\pm\sqrt[]{12}}{2} \\ x=\frac{6\pm\sqrt[]{4\cdot3}}{2} \\ x=\frac{6\pm2\sqrt[]{3}}{2} \\ x=3\pm\sqrt[]{3} \\ x_1=3-\sqrt[]{3} \\ x_2=3+\sqrt[]{3} \end{gathered}$

Then, the solutions to the equation are:

x = 0

x = 3 - √3

x = 3 + √3

4 0

1 year ago

7-3x=x-4(2+x) please help

ss7ja [257]

$\huge\boxed{\text{This equation has no solution.}}$