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Whitepunk [10]
4 years ago
7

An adult’s body has 206 bones. Of these, 106 are in the feet, ankle, wrists, and hands. What fraction of an adult’s bones are in

the feet, ankles, wrists, and hands? Write the fraction in simplest form.
Mathematics
1 answer:
NemiM [27]4 years ago
7 0
Hey. Let me help you on this question.

In order for us to solve this question, we might need to look into it more in depth, and sort the information. It will help us organize our thoughts.

Adult's body has 206 bones. 106 are located in the feet, ankles, wrists, and hands. Let's form a ratio that we can later simplify.

\frac{106}{206}

As you can see, we have 106 bones that are located in the feet, ankles, wrists, and hands over the total amount of bones in the adult's body.

Question asks us to give ratio's simplest form, and in order for us to simplify it, we need to find the greatest common divisor, or GCD for short. <span>GCD is largest integer number that divides the given numbers.

In order for us to find it, we need to find a number that we can multiply the given numbers with in order to make them equal. 

106 can be multiplied by two to make 206, and this is the highest number we can multiply it by in order to get both equivalent numbers.

Our next step is to divide both of these numbers by two, and plug them in the ratio.

</span>\frac{106}{206} /2= \frac{53}{103}
<span>
Done. We have reached the simplest form of this ratio, and dividing it further will not grant us a simpler form.

Answer: \frac{53}{103} is the ratio between 106 bones found in the feet, ankles, wrists and hands over 206 amount of total bones found in the body.
</span>
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Find the solution to the differential equation<br><br> dB/dt+4B=20<br><br> with B(1)=30
natita [175]

Answer:

The solution of the differential equation is B=5+25e^{-4t+4}

Step-by-step explanation:

The differential equation \frac{dB}{dt}+4B=20 is a first order separable ordinary differential equation (ODE). We know this because a separable first-order ODE has the form:

y'(t)=g(t)\cdot h(y)

where <em>g(t)</em> and <em>h(y) </em>are given functions<em>. </em>

We can rewrite our differential equation in the form of a first-order separable ODE in this way:

\frac{dB}{dt}+4B=20\\\frac{dB}{dt}=20-4B\\\frac{dB}{dt}=4(5-B)\\\frac{1}{5-B}\frac{dB}{dt}=4

Integrating both sides

\frac{1}{5-B}\frac{dB}{dt}=4\\\frac{1}{5-B}\cdot dB=4\cdot dt\\\\\int\limits {\frac{1}{5-B}} \, dB=\int\limits {4} \, dt

The integral of left-side is:

\int\limits {\frac{1}{5-B}} \, dB\\\mathrm{Apply\:u-substitution:}\:u=5-B\\\int\limits {\frac{1}{5-B}} \, dB=\int\limits {\frac{1}{u}} \, dB\\\mathrm{du=-dB}\\-\int\limits {\frac{1}{u}} \,du\\\mathrm{Use\:the\:common\:integral}:\quad \int \frac{1}{u}du=\ln \left(\left|u\right|\right)\\-\int\limits {\frac{1}{u}} \,du =-\ln \left|u\right|\\\mathrm{Substitute\:back}\:u=5-B\\-\ln \left|5-B\right|\\\mathrm{Add\:a\:constant\:to\:the\:solution}\\-\ln \left|5-B\right|+C

The integral of right-side is:

\int\limits {4} \, dt = 4t + C

We can join the constants, and this is the implicit general solution

-\ln \left|5-B\right|+C=4t + C\\-\ln \left|5-B\right|=4t + D

If we want to find the explicit general solution of the differential equation

We isolate B

-\ln \left|5-B\right|=4t + D\\\ln \left|5-B\right|=-4t+D\\\left|5-B\right|=e^{-4t+D}

Recall the definition of |x|

|x|=\left \{ {{x, \:if \>x\geq \>0 } \atop {-x, \:if \>x0}} \right.

So

\left|5-B\right|=e^{-4t+D}\\5-B= \pm \:e^{-4t+D}\\B=5 \pm \:e^{-4t+D}\\B=5\pm \:e^{-4t}\cdot e^{D}\\B=5+Ae^{-4t}

where A=\pm e^{D}

Now B(1) =30 implies

B=5+Ae^{-4t}\\30=5+Ae^{-4}\\30-5=Ae^{-4}\\25e^{4}=A

And the solution is

B=5+(25e^{4})e^{-4t}\\B=5+25e^{-4t+4}

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Step-by-step explanation:

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harkovskaia [24]

The angles m∠x = m∠y because alternate interior angles are equal.

<h3>What is a parallelogram?</h3>

A parallelogramis a quadrilateral in which opposite sides are equal and parallel to each other.

The opposite angles are also congruent, whereas consecutive interior angles are supplementary.

In the quadrilateral ABCD:

m∠x = m∠y (alternate interior angles are equal)

The angles m∠x = m∠y because alternate interior angles are equal.

Find out more on parallelogram at: brainly.com/question/970600

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A right circular cone is undergoing a transformation in such a way that the radius of the cone is increasing at a rate of 1/2 in
Ivenika [448]

Answer:

The volume is decreasing at the rate of 1.396 cubic inches per minute

Step-by-step explanation:

Given

Shape: Cone

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r = 2

h = \frac{1}{3}

Required

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The volume of a cone is:

V = \frac{\pi}{3}r^2h

Differentiate with respect to time (t)

\frac{dV}{dt} = \frac{\pi}{3}(2rh \frac{dr}{dt} + r^2 \frac{dh}{dt})

Substitute values for the known variables

\frac{dV}{dt} = \frac{\pi}{3}(2*2*\frac{1}{3}* \frac{1}{2} - 2^2 *\frac{1}{3})

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}* \frac{1}{2} - \frac{4}{3})

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}(\frac{1}{2} - 1))

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}*- 1)

\frac{dV}{dt} = -\frac{\pi}{3}*\frac{4}{3}

\frac{dV}{dt} = -\frac{22}{7*3}*\frac{4}{3}

\frac{dV}{dt} = -\frac{22}{21}*\frac{4}{3}

\frac{dV}{dt} = -\frac{88}{63}

\frac{dV}{dt} =-1.396in^3/min

The volume is decreasing at the rate of 1.396 cubic inches per minute

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3 years ago
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