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2 years ago

(2x^2+7+10)-(x^2+2x-9)

Mathematics

1 answer:

svlad2 [7]2 years ago

6 0

Step-by-step explanation:

$2 {x}^{2} + 7 + 10 - ( {x}^{2} + 2x - 9) \\ 2 {x}^{2} + 7 + 10 - {x }^{2} - 2x + 9 \\ {x}^{2} - 2x + 26$

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Trapezoid ABCD has vertices A(1,6) B(-2,6) C(-10,-10) and D(20,-10). Find the measure of ABCD’s midsegment to the nearest tenth

Elina [12.6K]

Answer:

16.5 units

Step-by-step explanation:

The midsegment is the distance between the midpoints of the nonparallel sides of the trapezoid.

The trapezoid ABCD has vertices A(1,6) B(-2,6) C(-10,-10) and D(20,-10).

We want to find the midsegment of ABCD to the nearest tenth.

The midpoint of BC is;

$( \frac{ - 2 + - 10}{2} , \frac{6 + - 10}{2} ) = ( - 6, - 2)$

The midpoint of AD is :

$( \frac{1 + 20}{2} , \frac{6 + - 10}{2} ) = ( 10.5, - 2)$

The length of the midsegment is the distance from (-6,2) to (10.5,2)

$= |10 .5 - - 6| = 16.5$

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2 years ago

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3 years ago

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2 years ago

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yKpoI14uk [10]

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