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DedPeter [7]
4 years ago
8

27. Explain the Error Yuan is asked to evaluate the expression (-8)' on his exam, and writes that it is unsolvable because you c

annot evaluate a negative number to an even fractional power. Is he correct, and if so, why? If he is not correct, what is the correct answer?
Mathematics
1 answer:
DanielleElmas [232]4 years ago
3 0

Answer:

he is incorrect the answer is -4

Step by step explanation:

\sqrt[3]{-8^{2} }  \\\\\\\sqrt{-2^{2} } \\\\= -4

just because something is negative doesn't mean it cant still be divided

it will still be able to be divided but it will be a negative number

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10 cards are numbered from 1 to 10 and placed in a box. One card is selected at random and is not replaced. Another card is then
AlladinOne [14]

Answer:

\frac{2}{9}

Step-by-step explanation:

The prime numbers between 1 and 10 are;

1, 2, 3, 5, 7

The probability of drawing the first card = \frac{5}{10}

Since there is no replacement, the probability of drawing the second card = \frac{4}{9}

The probability of selecting two prime numbers between 1 and 10 without replacement = \frac{5}{10} × \frac{4}{9} = \frac{2}{9}

8 0
3 years ago
-Is ZFDE a possible name for the figure below? Explain.<br> E<br> D<br> F<br> It’s number 14
gregori [183]

Answer: Yes \angle FDE is one possible angle name

Another name is \angle EDF

When it comes to naming an angle this way, all we need to worry about is the vertex point. This is where the angle hinges (think of a door or a pair of scissors). In this case, the hinge or vertex point is at point D. The vertex is always the middle letter of any three-letter sequence. The order of the other two points does not matter.

This is why saying "angle FDE" is the same as "angle EDF".

8 0
3 years ago
he parking garage of a mall is underground. Dr. Taylor parks her car 2 floors below ground level. She plans to walk to the 3rd f
ad-work [718]

Answer:

she will travel 5 floors from her car to the 3rd floor.

4 0
3 years ago
Find the position function of a particle moving along a coordinate line that satisfies the given condition v(t) = 6t2 - 4t + 5,s
jarptica [38.1K]

Answer:

s(t) = 2t^{3} - 2t^{2} + 5t - 9

Step-by-step explanation:

The position is the integrative of the velocity.

We have that:

v(t) = 6t^{2} - 4t + 5

So

s(t) = \int {v(t)} \, dt

s(t) = \int {(6t^{2} - 4t + 5)} \, dt

s(t) = 2t^{3} - 2t^{2} + 5t + K

In which k is the constant of integration, which we use the initial condition to find.

s(1) = -4. So

-4 = 2*(1)^{3} - 2*(1)^{2} + 5(1) + K

K = -9

So

s(t) = 2t^{3} - 2t^{2} + 5t - 9

3 0
3 years ago
PLEASE HELP &lt;3
quester [9]

Answer:

-403/40

or

-10 3/40

or

-10.075

3 0
3 years ago
Read 2 more answers
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