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Deffense [45]
3 years ago
6

How to add and subtract mixed fractions

Mathematics
2 answers:
Kazeer [188]3 years ago
5 0

Find the Least Common Denominator (LCD)

Find the equivalent fractions.

Add or subtract the fractions and add or subtract the whole numbers.

Write your answer in lowest terms.

Naddik [55]3 years ago
3 0
Step 1 Find the least common denominator
Step 2 Find the equivalent fractions
Step 3 Add or subtract the whole numbers
Step 4 write your answer in lowest terms
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When a number is increased by 12, the results is equal to twice the number equation
Mila [183]

Let the number be x

x + 12 = 2(x + 12)

x + 12 = 2x + 24

x - 2x = 24 - 12

-x = 12

x = -12

The number is -12.

3 0
3 years ago
7(x — 6) = 3х +9<br><br> Helppp
Igoryamba
Answer: x=51/4
step by step explanation: ask if needed
6 0
2 years ago
Read 2 more answers
Solve for x. Round your answer to the nearest hundredth.<br> 2x^2-6x+3=0
pogonyaev

Step-by-step explanation:

2 {x}^{2}  - 6x + 3 = 0 \\ x =  \frac{ - b± \sqrt{ {b}^{2}  - 4ac} }{2a}  \\ x =  \frac{6± \sqrt{12} }{4}  \\ x = 2.4  \: or \: 0.6

7 0
2 years ago
−2x−x+8 please help cant figure it out
Trava [24]

Answer:

-3x+8

Step-by-step explanation:

−2x−x+8

Add the -2x to the -x and you get -3x.

-3x + 8 is the answer if you wrote your equation correctly...

4 0
3 years ago
The product of 3 consecutive even integers is equal to the cube of the first plus the square of the second plus twice the square
algol [13]

Answer:

6, 8 and 10  and  -2, 0, 2

There are two roots x = -2 and 6,    

but the since I don't believe 0 is an even number the answer is 6, 8 and 10

I was incorrect according to G0ggle zero is an even number so another answer is  -2, 0, 2

Step-by-step explanation:

read the question and convert the English to mathematics

x, y and z    even consecutive number

y = x+2

z = y+2 = x+4

and

xyz = x³ + y² + 2z²                                   substitiute x terms  in for y and z

x(x+2)(x+4)  = x³ + (x+2)² + 2(x+4)²           solve for x by graphing on DEMOS

                                                                 x = -2, 6  solved algebraically below

x = -2   y=0   z=2

x = 6    y=8   z=10

Checked both answers

xyz = x³ + y² + 2z²

-2(0)2 = -8 + 0 + 8                  when x = -2

   0   =  0

and

6(8)(10)  =  6³ + 8² +2(10)²      when x = 6

   480   =  216+64+200

             =  480

x(x+2)(x+4)  = x³ + (x+2)² + 2(x+4)²                           solved algebraically

(x²+2x)(x+4)   = x³ + x² +4x +4 + 2x² + 16x + 32

x³ + 6x² + 8x = x³ + x² +4x +4 + 2x² + 16x + 32

x³ + 6x² + 8x = x³ + 3x² + 20x + 36

      3x² - 12x - 36 = 0         factor out the 3

      3[x² - 4x - 12] = 0

       3(x+2)(x-6) = 0     x = -2 and -12

6 0
2 years ago
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