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ira [324]
3 years ago
15

Find the volume of the solid formed by revolving the region bounded by the graphs of y = x^3, x = 2, and y = 1 about the y-axis.

Mathematics
1 answer:
andrezito [222]3 years ago
3 0

Since the rotation is about the y-axis, I'll integrate by dy.

\displaystyle y=x^3\\x=\sqrt[3]y\\\\V=\pi \int \limits_1^8(2^2-(\sqrt[3]y)^2)\, dy\\V=\pi \Big[4x-\dfrac{3}{5}x^{\tfrac{5}{3}}\Big]_1^8\\V=\pi \left(4\cdot8-\dfrac{3}{5}\cdot8^{\tfrac{5}{3}\right-\left(4\cdot1-\dfrac{3}{5}\cdot1^{\tfrac{5}{3}\right)\right)\\V=\pi \left(32-\dfrac{96}{5}-\left(4-\dfrac{3}{5}\right)\right)\\V=\pi \left(\dfrac{64}{5}-\dfrac{17}{5}\right)\\V=\dfrac{47\pi}{5}

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Sal ordered a chair. He gave a deposit of 20% of the cost and will pay the rest when the chair is delivered. If he deposited $80
Dafna1 [17]

Answer: $320 dollars

Step-by-step explanation:

if he already paid $80 and 20% of 400 is 80 then you would just subtract 80 from 400 to get 320.

3 0
3 years ago
Help me please I really don’t get this
pishuonlain [190]

Answer:

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7 0
3 years ago
A college charters a bus for $1300 to take a group of students to see a Broadway production. When 14 more students join the trip
tiny-mole [99]
<span>let x = the original no. of students
then
(x+10) = the actual no. that went on the trip
:
 = the original cost per student
and
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:
Original cost - actual cost = $12.50
 -  = 12.50
multiply equation by x(x+10)
x(x+10)* - x(x+10)* = 12.50x(x+10)
Cancel the denominators

1500(x+10) - 1500x = 12.5x(x+10)
1500x + 15000 - 1500x = 12.5x^2 + 125x
Combine on the right to form a quadratic equation
0 = 12.5x^2 + 125x - 15000
Simplify, divide equation by 12.5
x^2 + 10x - 1200 = 0
You can use the quadratic formula; a=1; b=10; c=-1200, but this will factor to
(x + 40(x - 30) = 0
The positive solution is what we want here
x = 30 students in the original group
Check this by finding the cost per student for each scenario
1500/30 = $50.00; original cost
1500/40 = $37.50; actual cost
---------------------
saving: $12.50</span>
6 0
3 years ago
The test scores of students in a math class are 46, 40, 50, 43, 35, 41, 50, 42, 38, and 48. What is the mean of this set of data
zimovet [89]
Mean is the average. You would add up all the numbers and divide by how many numbers you have.  433/10=43.3
5 0
4 years ago
What are the x-intercepts of this function f(x)=x^2+5x-36?
Gnom [1K]
F(x)=x2+5x−36f(x)=x2+5x-36
(0)=x2+5x−36(0)=x2+5x-36
x=4,−9x=4,-9
y=(0)2+5(0)−36y=(0)2+5(0)-36
y=0+0−36y=0+0-36
y=−36y=-36
These are the xx and yy intercepts of the equation y=x2+5x−36y=x2+5x-36.
x-int: (4,0),(−9,0)(4,0),(-9,0)
y-int: (0,−36)(0,-36)


4 0
3 years ago
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