Answer:
0.3972 this is a answer of questions
The first step is to add 7 to both sides, applying the addition property of equality:

Answer:
A = 20sinθ(6 + 5 cosθ) cm²
Step-by-step explanation:
Drop perpendiculars DE and CF to AB.
Then, we have congruent triangles ADE and BCF, plus the rectangle CDEF.
The formula for the area of the trapezium is
A = ½(a + b)h
DE = 10sinθ
AE = 10cosθ
BF = 10cosθ
EF = CD = 12 cm
AB = AE + EF + BF = 10cosθ + 12 + 10 cosθ = 12 + 20cosθ
A = ½(a + b)h
= ½(12 +12 + 20 cosθ) × 10 sinθ
=(24 + 20 cosθ) × 5 sinθ
= 4(6 + 5cosθ) × 5sinθ
= 20sinθ(6 + 5 cosθ) cm²
Solution: We are given:

We know that a usual values of the test scores falls within 2 standard deviation from the mean.
Therefore, the minimum usual test score is:




The maximum usual test score is:




Therefore, the minimum and maximum “usual” values of the test scores are:
65.4 and 90.6
9514 1404 393
Answer:
D. 5.4
Step-by-step explanation:
The point U divides segment SP into the ratio 1 : 2. So, segment SU is 1/2 the length of segment UP.
SU = UP/2 = 3.6/2 = 1.8
The length of PS is ...
PS = PU +US = 3.6 +1.8
PS = 5.4
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<em>Additional comment</em>
If you were asked to find the value of x, you would discover x=1. That is not what you're asked here.