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3 years ago

Which of the following statements is true?

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

5 0

<span>C. Lines FB and BA are perpendicular to each other.
[ Look at the sign of Perpendicular ]

Hope this helps!</span>

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In “Socialism vs. Capitalism: Which is the Moral System”, author C. Bradley Thompson refers to _____ as the only moral and just

frosja888 [35]

Answer: B. Capitalism

Step-by-step explanation:

7 0

3 years ago

Can 16, 19, and 34 form a triangle? Show your work.

I am Lyosha [343]

yes, since a+b > c for all sides

3 0

4 years ago

9 coins that equal 76 cents

Korvikt [17]

3 quarters and 1 penny

5 0

4 years ago

Read 2 more answers

Pumping stations deliver oil at the rate modeled by the function D, given by d of t equals the quotient of 5 times t and the qua

goblinko [34]

<h2>Hello!</h2>

The answer is: There is a total of 5.797 gallons pumped during the given period.

To solve this equation, we need to integrate the function at the given period (from t=0 to t=4)

The given function is:

$D(t)=\frac{5t}{1+3t}$

So, the integral will be:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dx$

So, integrating we have:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dt=5\int\limits^4_0 {\frac{t}{1+3t}} \ dx$

Performing a change of variable, we have:

$1+t=u\\du=1+3t=3dt\\x=\frac{u-1}{3}$

Then, substituting, we have:

$\frac{5}{3}*\frac{1}{3}\int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du\\\\\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u}{u} -\frac{1}{u } \ du$

$\frac{5}{9} \int\limits^4_0 {(\frac{u}{u} -\frac{1}{u } )\ du=\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u } )$

$\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u })\ du=\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du$

$\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du=\frac{5}{9} (u-lnu)/[0,4]$

Reverting the change of variable, we have:

$\frac{5}{9} (u-lnu)/[0,4]=\frac{5}{9}((1+3t)-ln(1+3t))/[0,4]$

Then, evaluating we have:

$\frac{5}{9}((1+3t)-ln(1+3t))[0,4]=(\frac{5}{9}((1+3(4)-ln(1+3(4)))-(\frac{5}{9}((1+3(0)-ln(1+3(0)))=\frac{5}{9}(10.435)-\frac{5}{9}(1)=5.797$

So, there is a total of 5.797 gallons pumped during the given period.

Have a nice day!

4 0

3 years ago

Use distribute property and simplify<br> Help me please

stellarik [79]

Answer:

104

155

180

Step-by-step explanation:

an easy way is to solve what is in the parenthesis then multiply by the outside number

but if you need to use the distributive property:

1. 4 x (20 - -6)

(4 x 20) - (4 x -6) = 80 - -24 = 80 + 24 = 104

2. -5 x (24 - -7)

(-5 x 24) - (-5 x -7) = -120 - 35 = 155

3. 12 x (-30 + 45)

(12 x -30) + (12 x 45) = -360 + 540 = 180

5 0

3 years ago

Read 2 more answers