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liubo4ka [24]
3 years ago
15

Please help, me and my brother have tried to solve this problem but couldn’t! Thanks!

Mathematics
2 answers:
vredina [299]3 years ago
6 0

m = (y1 - y2) / (x1 - x2)

m = zero slope

(I counted the rest of them)

shutvik [7]3 years ago
3 0

slope between 2 points (x_1,y_1) and (x_2,y_2) is

slope=\frac{y_2-y_1}{x_2-x_1}


so

given the points (4,\frac{-3}{5}) and (-4,\frac{-1}{3})

(x,y)

x_1=4

y_1=\frac{-3}{5}

x_2=-4

y_2=\frac{-1}{3}

so the slope is

slope=\frac{\frac{-1}{3}-\frac{-3}{5}}{-4-4}

note: -1/3-(-3/5)=-1/3+3/5=-5/15+9/15=4/15, and (a/b)/c=a/(bc)

slope=\frac{\frac{4}{15}}{-8}

slope=\frac{4}{(15)(-8)}

slope=\frac{4}{-120}

slope=\frac{-1}{30}


the slope is -1/30

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Vikentia [17]
77-27= 50 so when you add both it add up to 77 ,
50 is the answer 
6 0
3 years ago
Read 2 more answers
To estimate the difference we need four averages for the categorized groups i.e., control group before change, control group aft
nataly862011 [7]

Answer:

b. False

Step-by-step explanation:

In a research study, when a researcher wants to find the impact of a new treatment, then the researcher randomly divides the the study participants into two groups. The groups are :

-- control group

-- treatment group

The control group is a group that is used to establish the cause-and-effect relationship by making the effect of an independent variable isolate. It receives no treatment or some standard treatment for the which the effect is already known.

The treatment group receives the treatment for which the effect the researcher is interested in.

Thus the averages of the four categorized groups are not required for estimating the difference.

Therefore, the answer is FALSE.

3 0
3 years ago
5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.
s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of <em>(</em><em>124</em><em> </em><em>and</em><em> </em><em>244</em><em>)</em><em> </em>and <em>(</em><em>4424</em><em> </em><em>and</em><em> </em><em>2111</em><em>)</em><em> </em>are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

<em>#initialize</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>named</em><em> </em><em>gcd</em><em> </em><em>which</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>

if a>b:

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>b</em>

return gcd (b, a)

<em>#if</em><em> </em><em>true</em><em> </em><em>interchange</em><em> </em><em>the</em><em> </em><em>Parameters</em><em> </em><em>and</em><em> </em><em>Recall</em><em> </em><em>the</em><em> </em><em>function</em><em> </em>

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

<em>#even</em><em> </em><em>numbers</em><em> </em><em>leave</em><em> </em><em>no</em><em> </em><em>remainder</em><em> </em><em>when</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>2</em><em>,</em><em> </em><em>checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>even</em><em> </em>

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>odd</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>even</em><em> </em>

return gcd(a, b/2)

else :

return gcd(a, b-a)

<em>#since</em><em> </em><em>it's</em><em> </em><em>a</em><em> </em><em>recursive</em><em> </em><em>function</em><em>,</em><em> </em><em>it</em><em> </em><em>recalls</em><em> </em><em>the function</em><em> </em><em>with </em><em>new</em><em> </em><em>parameters</em><em> </em><em>until</em><em> </em><em>a</em><em> </em><em>certain</em><em> </em><em>condition</em><em> </em><em>is</em><em> </em><em>satisfied</em><em> </em>

print(gcd(124, 244))

print()

<em>#leaves</em><em> </em><em>a</em><em> </em><em>space</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>output</em><em> </em>

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0
2 years ago
Can you check my answers and help with number 3?
mamaluj [8]

Answer: Question 1 :B,D.

Question 2:option B,

Question 3:Degree=5.

Question 4:option D.

Question 5: option c.


Step-by-step explanation:

1) A polynomial can not have any exponent as a variable or a fraction.

Options B and D are polynomials.

2) The polynomial is having 3 terms and is of degree 3.so it is a cubic trinomial Option B.

3) Degree is the highest power of the variables in the terms .The term 6x^{3} y^{2} has the power=3+2=5

So degree =5.

4)(5x-2+3x^{2} )+(4x+3)=3x^{2} +5x+4x-2+3=3x^{2}+9x+1.

Option D


5)(5x^{2} +2x-5)-(3x^{2}+3x+1)= 5x^{2}+2x-5-3 x^{2}-3x-1

Simplifying like terms,

=2x^{2}-x-6.

Option c.


6 0
3 years ago
assuming that no questions are left unanswered, in how many ways can a six-question quiz with 4-choice multiple choice questions
AfilCa [17]

Given:

Total number of questions = 6

Choice for each question (in MCQ) = 4

Assuming that no questions are left unanswered.

To find:

The total number ways to answer the quiz, assuming that no questions are left unanswered.

Solution:

Here, Number of ways to answer each question = 4

To find the  total number ways to answer 6 MCQ, we have to have to multiply number of ways to answer each question 6 times.

Total number of ways to answer six-question quiz with 4-choice multiple choice questions is

4\times 4\times 4\times 4\times 4\times 4=4096

Therefore, the required number of ways is 4096.

3 0
3 years ago
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