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4 years ago

15

Please help, me and my brother have tried to solve this problem but couldn’t! Thanks!

2 answers:

vredina [299]4 years ago

6 0

m = (y1 - y2) / (x1 - x2)

m = zero slope

(I counted the rest of them)

shutvik [7]4 years ago

3 0

slope between 2 points $(x_1,y_1)$ and $(x_2,y_2)$ is

$slope=\frac{y_2-y_1}{x_2-x_1}$

so

given the points $(4,\frac{-3}{5})$ and $(-4,\frac{-1}{3})$

(x,y)

$x_1=4$

$y_1=\frac{-3}{5}$

$x_2=-4$

$y_2=\frac{-1}{3}$

so the slope is

$slope=\frac{\frac{-1}{3}-\frac{-3}{5}}{-4-4}$

note: -1/3-(-3/5)=-1/3+3/5=-5/15+9/15=4/15, and (a/b)/c=a/(bc)

$slope=\frac{\frac{4}{15}}{-8}$

$slope=\frac{4}{(15)(-8)}$

$slope=\frac{4}{-120}$

$slope=\frac{-1}{30}$

the slope is -1/30

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765ab4 is divisible by 36. Compute all ordered pairs (a, b) for which this is possible

tia_tia [17]

Answer:

All the ordered pairs (a,b) are

(0,5), (2,3), (4,1), (6,8), and (8,6).

Step-by-step explanation:

765ab4 to be divisible by 36, it must be divisible by both 9 and 4.

For any number to be divisible by 4, the last two digits of the number must be divisible by 4.

Here, the last two digits are b4, so as the number b4 is divisible by 4, b can be 0,2,4,6, and 8.

For any number to be divisible by 9, the sum of all the digit of the number must be divisible by 9.

Here, the sum of all the digits, S= 7+6+5+a+b+4=22+a+b.

Now, we have b={0,2,4,6, 8}

For b=0,

S=22+a+0=22+a which is a multiple of 9.

So, the possible value of the digit a :

a=5

So, (a,b)=(0,5)

For b=2,

S=22+a+2=24+a which is a multiple of 9.

So, the possible value of the digit a :

a=3

So, (a,b)=(2,3)

For b=4,

S=22+a+4=26+a which is a multiple of 9.

So, the possible value of the digit a :

a=1

So, (a,b)=(4,1)

For b=6,

S=22+a+6=28+a which is a multiple of 9.

So, the possible value of the digit a :

a=8

So, (a,b)=(6,8)

For b=8,

S=22+a+8=30+a which is a multiple of 9.

So, the possible value of the digit a :

a=6

So, (a,b)=(8,6)

Hence, all the ordered pairs (a,b) are

(0,5), (2,3), (4,1), (6,8), and (8,6).

3 0

3 years ago

If Charlie had 28 grapes and Tristan has 23 grapes how many grapes do they have in total

Debora [2.8K]

Answer:

51

Step-by-step explanation:

28 + 23 = 51

8 0

3 years ago

Read 2 more answers

Please Help Identify each angle pair. Choose from the list below.

Slav-nsk [51]

Answer:

The answer is given below.

Step-by-step explanation:

Alternate exterior angles: I is a pair of angles on the outer side of the each of two parallel lines but on opposite side of the transversal.

Vertically opposite angles: They are angles opposite each other when two lines intersect each other or cross each other.

Corresponding angles: The angles which occupy the same relative position at each intersection where a transversal intersect the two parallel lines.

Same side interior angles: These are the angles between the parallel lines with the transversal.

Alternate interior angles: These are those angles that are alternate to each other and lie inside the parallel lines forming in Z shape.

Linear pair angles: It is a pair of adjacent angles formed by two intersecting lines

$\angle 1\ and\ \angle 6:\ \textrm{alternate exterior angles}\\\angle 1\ and\ \angle 3:\ \textrm{Vertical opposite angles}\\\angle 3\ and\ \angle 6:\ \textrm{corresponding angles}\\\angle 4\ and\ \angle 8:\ \textrm{same side interior angles}\\\angle 4\ and\ \angle 5:\ \textrm{alternate interior angles}\\\angle 5\ and\ \angle 6:\ \textrm{linear pair angles}$

4 0

3 years ago

the sum of two numbers is 60. The second number is 5 times as much as the first number. What is the first number.

Oksanka [162]

Answer:

x = 10

The second number is 50

Step-by-step explanation:

Givens

The first number = x

The second number = 5x

Together when added the answer is 60

Equation

x + 5x = 60 Combine like terms

Solution

6x = 60 Divide by 6

6x/6 = 60/6

x = 10

5 0

3 years ago

The hawaiian alphabet has 12 letters. How many permutations are possible for five of these letters

guajiro [1.7K]

Answer: The answer is 50980

Step by Step Explanation:

First, temporarily assume that two letters with I are different, call them i 1 and i 2. Three "a" are also called as a 1, a 2 and a 3, and two h as h 1 and h 2. Then there are 11 * 10 * 9 * 8 * 7 = 55440 possible "words" (one of 11 is the first letter, 10 is the second, and so on). But because equal letters do the same "words," some "words" were counted twice or more. We have to deduct the number of "parasitic" counts although it is fairly small. The words that counted more than once are divided into many disjoint sets: 1) with two I but without repetitions of a and h; 2) with two h but without repetitions of a and I 3) with two a but without repetitions of I and h; 4) with three a but without repetitions of I and h; 5) with two I and two a's; 6) two i's and tree a's; 7) two i's and two h's 8) two h's and two a's; 9) two h's and one tree. The first category includes terms counted twice and its scale is (5 * 4) * (6 * 5 * 4) = 2400 (the first I stays at one of the 5 positions, the second at one of the 4, then 11-2i-1h-2a=6). So we have 2400/2 = 1200 to subtract. Group 2 gives -600 as well, and group 3 also. Group 4 gives * (6 * 5) = 1800 (5 * 4 * 3), and the terms are counted 6 times, -300. Groups 5, 7 , 8: 5 * 4 * 3 * 2 * 6 = 720 and counted four times, therefore -180. Group 6 and 9: 5 * 4 * 3 * 2 * 1 = 120, with 12 counts, -10. Altogether -(1200 * 3 + 300 + 180 * 3 + 10 * 2) = -4460.The answer will be 55440-4460 = 50980.

3 0

4 years ago