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liubo4ka [24]
3 years ago
15

Please help, me and my brother have tried to solve this problem but couldn’t! Thanks!

Mathematics
2 answers:
vredina [299]3 years ago
6 0

m = (y1 - y2) / (x1 - x2)

m = zero slope

(I counted the rest of them)

shutvik [7]3 years ago
3 0

slope between 2 points (x_1,y_1) and (x_2,y_2) is

slope=\frac{y_2-y_1}{x_2-x_1}


so

given the points (4,\frac{-3}{5}) and (-4,\frac{-1}{3})

(x,y)

x_1=4

y_1=\frac{-3}{5}

x_2=-4

y_2=\frac{-1}{3}

so the slope is

slope=\frac{\frac{-1}{3}-\frac{-3}{5}}{-4-4}

note: -1/3-(-3/5)=-1/3+3/5=-5/15+9/15=4/15, and (a/b)/c=a/(bc)

slope=\frac{\frac{4}{15}}{-8}

slope=\frac{4}{(15)(-8)}

slope=\frac{4}{-120}

slope=\frac{-1}{30}


the slope is -1/30

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8 0
3 years ago
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hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

d*sin(\theta) = m\lambda

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle              

At the first-order maximum (m=1) at 20.0 degrees we have:

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Now, to produce a second-order maximum (m=2) the angle must be:

sin(\theta) = \frac{\lambda}{d}*m

\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.    

I hope it helps you!                                                        

6 0
3 years ago
1/4 is to 2/3 as x is to 3/3?
ZanzabumX [31]

Answer: I think 59/100

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7 0
3 years ago
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